Transcript PPT
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Sets
Section 6.1 Basic Definitions of Sets Theory
Section 6.2 Properties of sets
Section 6.3 Proofs and Boolean Algebras
The most fundamental notion in all of mathematics is that of a set.
We say that a set is a specified collection of objects, called
elements (or members) of the set.
We denote sets by capital letters A, B, … and elements by lower
case letters, like x, y , … and so on. If an element x belongs to a set
A, we denote this by x A, if not we write x A.
Instructor: Hayk Melikya
Introduction to Abstract Mathematics
[email protected]
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Specifying set
There are various ways to specify a set. For the set of natural
numbers less than or equal to 5, you could write {1, 2, 3, 4, 5} .
For sets that cannot be specified by a list, we describe the
elements by some property common to the elements in the
set but no others, such as in the description
A = { x | P (x)}
which reads “the set of all x such that the condition P(x) is
true.”
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Common Sets:
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Subsets
We say that a set A is a subset of a set B if every element of A is also an
element of B.
Symbolically, we write this as A B and is read “A is contained in B.”
Finally, the notation A B means that A is not a subset of B.
Sets are often illustrated by Venn diagrams, where sets are represented
as circles and elements of the set are points inside the circle.
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Equality of Sets:
Two sets are equal (A = B) if they consist of exactly the same elements.
In other words, they are equal if
(A = B) if and only if (x) (( xA x B)
or
(A = B) iff (x) (( xA x B) (xB x A ))
another way:
(A = B) if and only if (A B B A).
Empty Set: The set with no elements is called the empty set (or null set) and
denoted by the Greek letter (or sometimes the empty bracket { } )
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Theorem 1 (Guaranteed Subset)
For any set A, we have A.
Proof :
Since the goal is to show
xxA
our job is done before we begin.
The reason being that the hypothesis x of the implication is false, being
that contains no elements, hence the proposition is true regardless of the
set A. In other words is a subset of any set.
END
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Theorem 2 (Transitive Subsets) Let A, B and C be sets.
If A B and B C then A C .
Proof:
We will prove the conclusion A C and use the hypothesis as needed.
Letting x A the goal is to show x C . Since x A and using the
assumption A B , we know x B . But the second hypothesis says
B C , and so we know x C . Hence, we have proved A C , which
proves the theorem.
END
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Subset and Membership:
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Power Set P(A)
An important set in mathematics is the power set.
For every set A, we denote by P(A) the set of all subsets of A.
Theorem 3 (Power Set) Let A and B be sets.
Then A B if and only if P (A) P(B).
Proof:
(A B) (P(A) P(B)):
We start by letting X P(A) and show X P(B) (and use A B as
our “helper”). Letting X P(A) we have X A and hence X B. But
this means X P(B) and so we have shown P(A) P(B) .
(P(A) P(B)) (A B) :
We let x A and show x B . If x A, then {x } P(A) , and since
P(A) P(B) we know {x } P(B) . But this means x B and so A B .
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Sec 6.2 Operations on Sets Union, Intersection and
Complement
In traditional arithmetic and algebra, we carry out the binary operations of
+ and × on numbers. In logic, we have the analogous binary operations
of and on sentences. In set theory we have the binary operations of
union and intersection of sets, which in a sense are analogous to the
ones in arithmetic and sentential logic.
Definition ( Union): The union of two sets A and B, denoted
A B , is the set of elements that belong to A or B or both.
Symbolically
A B = {x | x A x B }
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Definition ( Intersection):
The intersection of two sets A and B, denoted A B , is the set
of elements that belong to A and B.
Symbolically
A B = {x | x A x B }
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Definition( Complement):
The compliment of A, denoted Ac is the set of elements
belonging to the universal set U but not A.
Symbolically
Ac = {x | x U x A } .
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Definition (Relative Complement or Difference):
The relative complement of A in B, denoted, B \ A, is the set of
elements in B but not in A.
Symbolically
B \ A = {x | x B x A }
The concepts of union, intersection and relative complement of sets
can be illustrated graphically by use of Venn diagrams.
Each Venn diagram begins with an oval representing the universal
set, a set that contains all elements of in discussion.
Then, each set in the discussion is represented by a circle, where
elements belonging to more than one set are placed in sections where
circles overlap.
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Venn diagrams for two overlapping sets.
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Set Identities
Commutative Laws: A B = A B and A B = B A
Associative Laws: (A B) C = A (B C) and (A B) C = A (B C)
Distributive Laws:
A (B C) = (A B) (A C) and A (B C) = (A B) (A C)
Intersection and Union with universal set: A U = A and A U = U
Double Complement Law: (Ac)c = A
Idempotent Laws: A A = A and A A = A
De Morgan’s Laws: (A B)c = Ac Bc and (A B)c = Ac Bc
Absorption Laws: A (A B) = A and A (A B) = A
Alternate Representation for Difference: A – B = A Bc
Intersection and Union with a subset: if A B, then A B = A and A B = B
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Exercises
Is is true that (A – B) (B – C) = A – C?
Show that (A B) – C = (A – C) (B – C)
Is it true that A – (B – C) = (A – B) – C?
Is it true that (A – B) (A B) = A?
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Set Partitioning
Two sets are called disjoint if they have no elements in common
Theorem: A – B and B are disjoint
A collection of sets A1, A2, …, An is called mutually disjoint when any pair of sets
from this collection is disjoint
A collection of non-empty sets {A1, A2, …, An} is called a partition of a set A when
the union of these sets is A and this collection consists of mutually disjoint sets
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Power Set
Power set of A is the set of all subsets of A
Theorem: if A B, then P(A) P(B)
Theorem:
If set X has n elements, then P(X) has 2n elements.
Proof. (By Induction)
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Boolean Algebra
Boolean Algebra is a set of elements together with two
operations denoted as + and * and satisfying the following
properties:
a + b = b + a, a * b = b * a
(a + b) + c = a + (b + c), (a * b) *c = a * (b * c)
a + (b * c) = (a + b) * (a + c), a * (b + c) = (a * b) + (a * c)
a + 0 = a, a * 1 = a for some distinct unique 0 and 1
a + ã = 1, a * ã = 0
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Exercises
Simplify: A ((B Ac) Bc)
Symmetric Difference: A B = (A – B) (B – A)
Show that symmetric difference is associative
Are A – B and B – C necessarily disjoint?
Are A – B and C – B necessarily disjoint?
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Russell’s Paradox
Set of all integers, set of all abstract ideas
Consider S = {A, A is a set and A A}
Is S an element of S?
Barber puzzle: a male barber shaves all those men who do
not shave themselves. Does the barber shave himself?
Consider S = {A U, A A}. Is S S?
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