Graph Reconstruction Conjecture
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Transcript Graph Reconstruction Conjecture
Graph Reconstruction
Conjecture
Graph Reconstruction Conjecture
Proposed by S.M. Ulan & P.J. Kelly in 1941:
The conjecture states that every graph with at
least 3 vertices is reconstructible; a graph G
is reconstructible if it is defined by its vertexdeleted subgraphs.
Definitions
v1
v2
G=
v4
v3
DECK = the multi-subset of vertex-deleted
subgraphs of G
v2
v1
v1
v2
v1
v2
D(G) =
v4
v3
v4
v3
v4
v3
CARD = a vertex-deleted subgraph of G
(we do not worry about graphs that are different
through labelling nodes differently, but are isomorphic)
Graph reconstruction
Can we obtain G from D(G)?
D(G) =
Graph reconstruction
Can we obtain G from D(G)?
D(G) =
G=
Graph Reconstruction Conjecture
Every graph with at least three vertices is reconstructible
Unproven
Verified for regular graphs (graphs in which all vertices
have same number of edges).
Verified for all graphs with at most 11 vertices.
Bollobás: Used probability to show that almost all
graphs are reconstructible; probability that a randomly
chosen graph with n vertices is not reconstructible
approaches zero as n approaches infinity.
For almost all graphs, there exist 3 cards that uniquely
determine the graph.
Reconstruction Number
rn(G)
The number of cards required to reconstruct
the original graph.
> 2 because at least 2 different graphs can be
generated from a deck of 2 (difference
between the 2 graphs is 1 edge)
Reconstruction Number Logic
1.
2.
3.
Get all cards of a given deck
Extend the cards
The intersection of the extended cards is the
solution
Conjecture: rn(G) is at most (n/2 +1)
•
Bollobás used proof via probability to prove
rn(G) is at least 3
Finding Reconstruction Number
v1
v2
G=
v4
1.
v3
Get all cards of a given deck
v2
v4
v4
D(G) =
v4
v3
v1
v3
v1
v2
v1
v2
v3
Finding Reconstruction Number
v2
v4
v4
D(G) =
v1 deck
v2
1.
Get vall
cards
of
v3
v3
v1 a given
4
2.
Extend the cards
=>
=>
=>
v1
v2
v3
Finding Reconstruction Number
v2
v4
v4
v1
2.
Get all cards of a given deck
D(G) =
v
v
v
v
Extend the cards
v
3.
The intersection of the extended cards is the solution
1.
4
=>
=>
=>
3
1
3
1
v2
v2
v3
Proven generally not reconstructible:
Digraphs (AKA Directed graph)
Hypergraphs: edges can connect to any
number of vertices.
Infinite Graphs: Infinitely many vertices
and/or edges