Transcript CA 208 Logic - DCU School of Computing

CA 208 Logic
First-Order Predicate Logic
Kate is a student.
Every student is broke.
----------------------------Kate is ???
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CA 208 Logic

Propositional Logic is not enough ... 
Kate is a student.
Every student is broke.
----------------------------Kate is broke.
P
Q
-R
Is that a valid inference in propositional logic?
Sokrates is human.
Every human is mortal.
----------------------------Sokrates is mortal.
W
S
-T
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CA 208 Logic

Propositional Logic is not enough ... 
Kate is a student.
Every student is broke.
----------------------------Kate is broke.
P
Q
-R
Is that a valid inference in propositional logic?
Sokrates is human.
Every human is mortal.
----------------------------Sokrates is mortal.
W
S
-T
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CA 208 Logic

Propositional Logic is not enough ... 
Kate is a student.
Every student is broke.
----------------------------Kate is broke.
P
Q
-R
Is that a valid inference in propositional logic?
Sokrates is human.
Every human is mortal.
----------------------------Sokrates is mortal.
W
S
-T
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CA 208 Logic

Propositional Logic is not enough ... 
7 is a prime number.
Every prime number is odd.
----------------------------7 is odd.
P
Q
-R
Kate is a student.
----------------------------Somebody/thing is a student.
W
-T
Kate owns Google.
----------------------------Kate owns something.
U
-V
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CA 208 Logic




Propositional Logic is not enough ... 
Propopsitional logic is not fine-grained (expressive)
enough to capture many of these intuitively valid
inferences
In fact translated into propositional logic they would give
you non-valid inference schemas (and you have seen
lots of them on the previous slides)
The problem is that propositional logic can not go inside
atomic propositions (sentences) and all we get is P, Q,
R, etc...
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CA 208 Logic



So what do we need to caputure those inferences?????
We need a logic that can break down atomic propositions into
(some of) their constituent parts and make explicit how they fit
together
Need to be able to talk about

Individuals: Kate, 7, Google, ...
Properties of individuals: being a student, human, prime number, ...
Relationships between individuals: a owns b, ...
Quantifiers and variables: every, some, ...

Thats what (First-Order) Predicate Logic (FOPL) gives you!



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CA 208 Logic

Propositional Logic is not enough ... 
Kate is a student.
Every student is broke.
----------------------------Kate is broke.
P
Q
-R
student(k)
x (student(x)broke(x))
---------------------------------broke(k)
Sokrates is human.
Every human is mortal.
----------------------------Sokrates is mortal.
W
S
-T
human(s)
x (human(x)mortal(x))
---------------------------------mortal(s)
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CA 208 Logic

Propositional Logic is not enough ... 
Kate is a student.
Every student is broke.
----------------------------Kate is broke.
P
Q
-R
student(k)
x (student(x)broke(x))
---------------------------------broke(k)
Sokrates is human.
Every human is mortal.
----------------------------Sokrates is mortal.
W
S
-T
human(s)
x (human(x)mortal(x))
---------------------------------mortal(s)
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CA 208 Logic

Propositional Logic is not enough ... 
Kate is a student.
Every student is broke.
----------------------------Kate is broke.
P
Q
-R
student(k)
x (student(x)broke(x))
---------------------------------broke(k)
Sokrates is human.
Every human is mortal.
----------------------------Sokrates is mortal.
W
S
-T
human(s)
x (human(x)mortal(x))
---------------------------------mortal(s)
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CA 208 Logic

Propositional Logic is not enough ... 
7 is a prime number.
Every prime number is odd.
----------------------------7 is odd.
P
Q
-R
prime(7)
x (prime(x)odd(x))
----------------------------odd(7)
Kate is a student.
----------------------------Somebody/thing is a student.
W
-T
student(k)
---------------x student(x)
Kate owns Google.
----------------------------Kate owns something.
U
-V
own(k,g)
--------------x own(k,x)
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CA 208 Logic

Translation key:
7  7, prime number  prime(_), odd  odd(_)
7 is a prime number.
Every prime number is odd.
----------------------------7 is odd.

prime(7)
x (prime(x)odd(x))
----------------------------odd(7)
Translation key:
Kate  k, Google  g, own  own(_,_)
Kate owns Google.
----------------------------Kate owns something.
own(k,g)
--------------x own(k,x)
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CA 208 Logic

And now something amazing happens:
Kate is a student.
Every student is broke.
----------------------------Kate is broke.
student(k)
x (student(x)broke(x))
---------------------------------broke(k)
P(j)
x (P(x)Q(x))
-------------------Q(j)
Sokrates is human.
Every human is mortal.
----------------------------Sokrates is mortal.
human(s)
x (human(x)mortal(x))
---------------------------------mortal(s)
P(j)
x (P(x)Q(x))
-------------------Q(j)
7 is a prime number.
Every prime number is odd.
----------------------------7 is odd.
prime(7)
x (prime(x)odd(x))
----------------------------odd(7)
P(j)
x (P(x)Q(x))
-------------------Q(j)
Do you see what these guys have in common??
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CA 208 Logic

And now something amazing happens:
Kate is a student.
Every student is broke.
----------------------------Kate is broke.
student(k)
x (student(x)broke(x))
---------------------------------broke(k)
P(j)
x (P(x)Q(x))
-------------------Q(j)
Sokrates is human.
Every human is mortal.
----------------------------Sokrates is mortal.
human(s)
x (human(x)mortal(x))
---------------------------------mortal(s)
P(j)
x (P(x)Q(x))
-------------------Q(j)
7 is a prime number.
Every prime number is odd.
----------------------------7 is odd.
prime(7)
x (prime(x)odd(x))
----------------------------odd(7)
P(j)
x (P(x)Q(x))
-------------------Q(j)
Do you see what these guys have in common?? The inference doesn’t depend on your
particular choice of individuals, poperties and relations! Just the pattern .....!
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CA 208 Logic
Syntax of First-Order Predicate Logic FOPL
Lexicon (the basic words in the language of FOPL)

Particular individuals = constant symbols: {k,l,m, ...}

Arbitrary individuals = variable symbols: {x, y, z,...}

Properties of individuals = 1-place predicates: {human(_), prime(_), broke(_), ...}

Relations between individuals = n-place predicates: {own(_,_), buy(_,_),
give(_,_,_), ...}

Quantifiers over individuals = forall, exists: {,}

Logical connectives (unary and binary): {,  , , } (from propositional logic!)

Brackets: {‘(‘,’)’}
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CA 208 Logic
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
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Let Var be a (countably infinite) set of variables Var = {x,y,z, ...}
Let Const be a (countably infinite) set of constants Const = {a,b,c, …}
Let Π be a (countably infinite ...) set of predicate symbols Π = {P¹_1,…, P¹_m,… ,
P²_1, ..., P²_m,…, Pⁿ_1, ..., Pⁿ_m,...}, for each arity 1 to n

Terms = Var  Const

If t¹, …, tⁿ  Terms and Pⁿ  Π, then Pⁿ(t¹, …, tⁿ)  WFF
(atomic formulas)

If Φ  WFF, then Φ  WFF
(complex formulas)




If Φ, Ψ  WFF, then (Φ  Ψ)  WFF
If Φ, Ψ  WFF, then (Φ  Ψ)  WFF
If Φ, Ψ  WFF, then (Φ  Ψ)  WFF
If Φ, Ψ  WFF, then (Φ  Ψ)  WFF

If α Var and Φ WFF, then α Φ  WFF
If α Var and Φ WFF, then α Φ  WFF

Nothing else is a formula.

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CA 208 Logic


A particular choice of
 Var
 Const
 Π
fixes a particular language of FOPL
E.g. let



Var = {x,y,z, ...}
Const = {j, k, l, g, 7, …}
Π = {human¹, student¹, broke¹, prime¹, odd¹, own²}
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CA 208 Logic
Which of the following are WWFs in the particular FOPL language fixed in previous slide?
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
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
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


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human(k)
human(student)
prime(k)
prime(7)
human(k,j)
prime(7)
own(k,g)
own(k j,g)
prime(7)  human(k)
(prime(7)  human(k))
(prime(7)  human(k))
(prime(7)  human(k))
(prime(7)  human(k))
x broke(x)
k
x own(x,g)
x own(x,x)
x own(x,x,x)
x y own(x,y)
xy own(x,y)
xy own(x,y)
x (human(x)  own(x,g))
x odd(x)
x (odd(x))
x even(x)
odd(5)
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CA 208 Logic
Translate the following into FOPL:







Kate is human
7 is prime
7 is not prime
Kate owns Google
Somebody owns Google.
Every student is broke.
A student is broke.
human(k)
prime(7)
prime(7)
own(k,g)
x own(x,g)
x (student(x)  broke(x))
x (student(x)  broke(x))
Question: why not

Every student is broke.
x (student(x)  broke(x))
???
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CA 208 Logic
Translate the following into FOPL:






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Kate is human
7 is prime
7 is not prime
Kate owns Google
Somebody owns Google.
Every student is broke.
A student is broke.
human(k)
prime(7)
prime(7)
own(k,g)
x own(x,g)
x (student(x)  broke(x))
x (student(x)  broke(x))
Question: why not

Every student is broke.
x (student(x)  broke(x))
???
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CA 208 Logic
Translate the following into FOPL:







Kate is human
7 is prime
7 is not prime
Kate owns Google
Somebody owns Google.
Every student is broke.
A student is broke.
human(k)
prime(7)
prime(7)
own(k,g)
x own(x,g)
x (student(x)  broke(x))
x (student(x)  broke(x))
Question: why not

Every student is broke.
x (student(x)  broke(x))
???
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CA 208 Logic
We’ll develop syntactic |- and semantic |= consequence relations for FOPL
Why? Because thats what logic is about: remember, logic tell you what follows from
what ....

First we’ll do |-

We’ll use the Natural Deduction (ND) proof system

The good news is that everything we learned about ND in Propositional Logic
carries over to FOPL : all the introduction and elimination rules for the binary
connectives and all the rules for negation

What else do we need?

We need ND rules for the quantifiers (and then we are done) ...

This being ND, the quantifier rules come in pairs: we have an introduction rule
amd an elimination rule for each of the quantifiers {,}
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CA 208 Logic
Introduction
П1 П2
:
:
A
B
---------- (I)
AB
П
П
:
:
A
A
--------- (I) -------- (I)
AB
BA
Elimination
П
:
AB
--------- (E)
A
П
:
A B
-------- (E)
B
П
[A]ass
[B]ass
:
:
:
AB
C
C
----------------------------------------- (E)
C
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CA 208 Logic
Introduction
[A]ass
:
B
------- (→I)
A→B
Elimination
П1
П2
:
:
A
A→B
---------------- (→E)
B
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CA 208 Logic
Introduction
[A]ass
:

------- ( I)
A

----- (ex falso quod libet)
A
Elimination
П1
П2
:
:
A
A
---------------- ( E)

[A]ass
П
:
or
:

A
-----------A
A
or
--------A  A
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CA 208 Logic
Introduction
П
:
P(c)
------- ( I)
x P(c)[x/c]
*¹
П
:
P(x)[c/x]
----------- ( I)
x P(x)
Elimination
П
:
x P(x)
---------- ( E)
P(x)[c/x]
П
[P(x)[c/x]]ass
:
:
x P(x)
Q
-------------------- ( E) *²
Q
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CA 208 Logic
Lots of example proofs in ND here (on the blackboard ...) Fix a language of FOPL, e.g. let



Var = {x,y,z, ...}
Const = {j, k, l, g, 7, …}
Π = {human¹, student¹, broke¹, prime¹, odd¹, own²}
{x broke(x)} |- broke(k)
x broke(x)
--------------- ( E)
broke(k)
{x broke(x)} |- y broke(y)
x broke(x)
--------------- (E)
broke(k)
-------------- (I)
y broke(y)
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CA 208 Logic
{x (student(x)  broke(x)) student(k)} |- broke(k)
x (student(x)  broke(x))
---------------------------------- ( E)
student(k)
student(k)  broke(k)
--------------------------------------------------- (E)
broke(k)
{x (student(x)  broke(x)) student(k)} |- z broke(z)
x (student(x)  broke(x))
---------------------------------- ( E)
student(k)
student(k)  broke(k)
--------------------------------------------------- (E)
broke(k)
----------- (I)
z broke(z)
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CA 208 Logic
{own(k,g)} |- x own(k,x)
own(k,g)
------------- (I)
x own(k,x)
{} |- (own(k,g)  x own(k,x))
[own(k,g)]ass¹
------------- (I)
x own(k,x)
------------------------------ (I)¹
(own(k,g)  x own(k,x))
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CA 208 Logic
{own(k,g)} |- x y own(x,y)
own(k,g)
------------- (I)
y own(k,y)
------------- (I)
x y own(x,y)
{own(k,g)} |- x own(x,x)
??? Can’t do that in ND (and should not be able to!!) but:
{own(g,g)} |- x own(x,x)
own(g,g)
------------- (I)
x own(x,x)
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CA 208 Logic
{own(k,g)} |- x own(x,x)
??? Can’t do that in ND (and should not be able to!!) but:
{own(g,g)} |- x own(x,x)
own(g,g)
------------- (I)
x own(x,x)
{own(g,g)} |- x y own(x,y)
own(g,g)
------------- (I)
y own(g,y)
------------- (I)
x y own(x,y)
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CA 208 Logic
Introduction
П
:
P(c)
------- ( I)
x P(c)[x/c]
*¹
П
:
P(x)[c/x]
----------- ( I)
x P(x)
Elimination
П
:
x P(x)
---------- ( E)
P(x)[c/x]
П
[P(x)[c/x]]ass
:
:
x P(x)
Q
-------------------- ( E) *²
Q
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CA 208 Logic
Introduction
П
:
P(c)
------- ( I)
x P(c)[x/c]
*¹
П
:
P(x)[c/x]
----------- ( I)
x P(x)
Elimination
П
:
x P(x)
---------- ( E)
P(x)[c/x]
П
[P(x)[c/x]]ass
:
:
x P(x)
Q
-------------------- ( E) *²
Q
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CA 208 Logic
Introduction
П
:
P(c)
------- ( I)
x P(c)[x/c]
*¹
(side condition)
*¹: c does not occur in premise or open, undischarged
assumption on which P(c) depends. In other words
“c is a truly arbitrary constant symbol ….”
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CA 208 Logic
{broke(k)} |- x broke(x)
??? No!! Can’t do that in ND (and should not be able to!!) but:
{x broke(x)} |- z broke(z)
x broke(x)
--------------- (E)
broke(g)
----------- (I)
z broke(z)
{x (student(x)  broke(x)), z student(z)} |- y broke(y)
z student(z)
---------------- (E)
student(k)
x (student(x)  broke(x))
-------------------------------- (E)
student(k)  broke(k)
---------------------------------------------(E)
broke(k)
------------- (I)
y broke(y)
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CA 208 Logic
Elimination
П
:
x P(x)
(side conditions)
[P(x)[c/x]]ass
:
Q
---------------------- ( E) *²
Q
*²: c does not occur in x P(x) nor in Q nor in any premise
or open (undischarged) assumption on which Q depends
(except [P(x)[c/x]]ass which is discharded by the proof).
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CA 208 Logic
Show that:
{x (student(x)  broke(x)), z student(z)} |- y broke(y)
x (student(x)  broke(x))
---------------------------------- (E)
[student(k)ass]¹
student(k)  broke(k)
-------------------------------------------------- (E)
broke(k)
---------- (I)
z student(z)
y broke(y)
-------------------------------------------------- (E)¹
y broke(y)
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CA 208 Logic
There is method in the madness ...:
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
Introduction rules
Elimination rules
for each connective.
Premisses are “resources” from which to construct conclusions.


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Some times complex premises need to be broken apart to get at the
components (as they are used in the conclusion): elimination rules
Sometimes simple premises need to be put together into more
complex formulas (as they are used in the conclusion): introduction
rules
Sometimes you need a bit of both in a proof: elimination rules and
introduction rules
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CA 208 Logic
There is method in the madness ...:


Introduction rules
Elimination rules
for each connective.
This gives an inherent symmetry to Natural Deduction Rules/Calculus



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Some times logicians wax lyrical about this ... 
You have seen the Gentzen/Prawitz-style formulation of ND for FOPL
Thats not the only one – but its nice as the proof rules for the quantifiers
work for both intuitionistic and classical versions of FOPL
Other formulation of ND for FOPL (classical only): ... Quine (1959), Suppes
(1957), Copi (1954)
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CA 208 Logic
{P_1, ..., P_n} |- C iff
P_1, ..., P_n, [A_1]ass, ...,[A_m]ass
ND
C
without any open (undischarged) intermediate assumptions
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CA 208 Logic


Up to now we have defined |- for FOPL (syntactic consequence relation)
Now we’ll define |= for FOPL (semantic consequence relation)
Recall:

{P_1, ..., P_n} |= C iff in all the situations in which all of P_1 to P_n are true, C is true
as well
Or, equivalently

{P_1, ..., P_n} |= C iff you can not come up with a single situation in which all of P_1
to P_n are true, and C is false
We’ll need to make this talk about “situations” (ways in which the world is or could be)
formal ...
We’ll do this in terms of models. Models are mathematical objects (non-empty sets with
relations defined on those sets) which represent “situations”.
These models will allow us then to interpret WFFs of FOPL as true or false, hence allow
us to define |= for FOPL formally ... thats da evil plan ...
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CA 208 Logic
These models will allow us then to interpret WFFs of FOPL as true or false, hence allow
us to define |= for FOPL formally ... thats da evil plan ...
Trouble is there are infinitely many WFFs ... (by the way, same for Propositional Logic)
So we’ll need a way of defining the truth/falsity of -many WFFs in a finite way ...
We’ll do this the same way we did it for Propositional Logic
We give a compositional semantics, where each syntactic formation (i.e.grammar) rule is
paired with a semantic interpretation rule ...
In other words: our syntax builds more and more complex objects out of simpler objects
(syntax is a inductive specification) and
Our semantics (semantic interpretation rules) recurses down from the complex to the
simpler objects and defines the meaning of the complex objects depending on the
meaning of its simpler component parts as defined by the syntax ...
Here is the syntax again ...
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CA 208 Logic



Let Var be a (countably infinite) set of variables Var = {x,y,z, ...}
Let Const be a (countably infinite) set of constants Const = {a,b,c, …}
Let Π be a (countably infinite ...) set of predicate symbols Π = {P¹_1,…, P¹_m,… ,
P²_1, ..., P²_m,…, Pⁿ_1, ..., Pⁿ_m,...}, for each arity 1 to n

Terms = Var  Const

If t¹, …, tⁿ  Terms and Pⁿ  Π, then Pⁿ(t¹, …, tⁿ)  WFF
(atomic formulas)

If Φ  WFF, then Φ  WFF
(complex formulas)




If Φ, Ψ  WFF, then (Φ  Ψ)  WFF
If Φ, Ψ  WFF, then (Φ  Ψ)  WFF
If Φ, Ψ  WFF, then (Φ  Ψ)  WFF
If Φ, Ψ  WFF, then (Φ  Ψ)  WFF

If α  Var and Φ  WFF, then α Φ  WFF
If α  Var and Φ  WFF, then α Φ  WFF

Nothing else is a formula.

43
CA 208 Logic


What’s a model?
A model is always a model for a specific language, so given a FOPL
language L with CONST = {j,k,m}, VAR = {x,y,z} and П = {student¹,
broke¹, like²}

M = < U, > is a model





where U  {} (U is called the “Universe”) and
 is an interpretation function interpreting all the constant symbols and
predicate symbols in the language
E.g.:
U = {□,◊,○}
(j) = □, (m) = ◊, (k) = ○ , (student) = {□,○}, (broke) = {□,○}
(like) = {<□,□>,<○,□>,<◊,○>}
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CA 208 Logic



Informally (!!) now ...
M = < U, > is a model where
 U = {□,◊,○}
 (j) = □, (m) = ◊, (k) = ○ , (student) = {□,○}, (broke) = {□,○}
(like) = {<□,□>,<○,□>,<◊,○>}
What’s the meaning (true/false) of
 student(m)
false
 student(j)
true
 student(k)
true
 broke(k)
true
 broke(m)
false
 like(k,j)
true
 like(k,k)
false
 like(j,j)
true
45
CA 208 Logic



Informally (!!) now ...
M = < U, > is a model where
 U = {□,◊,○}
 (j) = □, (m) = ◊, (k) = ○ , (student) = {□,○}, (broke) = {□,○}
(like) = {<□,□>,<○,□>,<◊,○>}
In this model M, what’s the meaning (true/false) of
 student(m)
false
 student(j)
true
 student(k)
true
 broke(k)
true
 broke(m)
false
 like(k,j)
true
 like(k,k)
false
 like(j,j)
true
46
CA 208 Logic

So far so good, but sth. is missing ...

M = < U, > is a model
 where U  {} (U is called the “Universe”) and
  is an interpretation function interpreting all the constant
symbols and predicate symbols in the language


We haven’t said anything about how to interpret the variables yet
... !
That’s the job of a variable assignment function g
g: Var ↦ U
(g is a total function from Var into U)

E.g.:

Actually, any way of fixing g does the job (why will become clear
later) ...

g(x) = ○, g(y)= ○, g(z)= ○,
47
CA 208 Logic




Let Var be a (countably infinite) set of variables Var = {x,y,z, ...}
Let Const be a (countably infinite) set of constants Const = {a,b,c, …}
Let Π be a (countably infinite ...) set of predicate symbols Π = {P¹_1,…,
P¹_m,… , P²_1, ..., P²_m,…, Pⁿ_1, ..., Pⁿ_m,...}, for each arity 1 to n
Let M = < U, > be a model







where U  {}
(c)  U, for each c  Const
(Pⁿ) ⊆ U x U x ... x U (n-times), for each Pⁿ  Π
Let g be a variable assignment/interpretation function g: Var ↦ U
We now define I_[M,g] : interpretation relative to a model M and variable
assignment function g
I_[M,g] (t) ≔ (t), if t  Const
I_[M,g] (t) ≔ g(t), if t  Var
(Terms)
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CA 208 Logic

I_[M,g] (Pⁿ(t¹, …, tⁿ)) ≔ 1 iff
< I_[M,g] (t¹), …, I_[M,g] (tⁿ)>  (Pⁿ)
(atomic formulas)







I_[M,g] (Φ) ≔ 1
iff
I_[M,g] (Φ) = 0
I_[M,g] (Φ  Ψ) ≔ 1
I_[M,g] (Φ  Ψ) ≔ 1
I_[M,g] (Φ  Ψ) ≔ 1
I_[M,g] (Φ  Ψ) ≔ 1
iff
iff
iff
iff
I_[M,g] (Φ) = 1
I_[M,g] (Φ) = 1
I_[M,g] (Φ) = 0
I_[M,g] (Φ)
I_[M,g] (α Φ) ≔ 1
I_[M,g] (α Φ) ≔ 1
iff for all u  U, I_[M,g(u/α)] (Φ) =1
iff for at least one u  U, I_[M,g(u/α)] (Φ) =1
(complex formulas)
and
or
or
=
I_[M,g] (Ψ) = 1
I_[M,g] (Ψ) = 1
I_[M,g] (Ψ) = 1
I_[M,g] (Ψ)
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CA 208 Logic

This is the classical Tarski-style definition of the interpretation of a WFF of a
particular language of FOPL in a model M, relative to an assignment function g.

Notice that (as for the case of Propositional Logic earlier on in the course) the
meaning of a WFF is unpacked using a distinction between object language (,
, , ... ) and meta-language (English: not, and, for all, ...)

Notice that in this Tarski-style definition, the interpretation I_[M,g] of a formula is
effectively truth relative to model M and variable assignment function g

Another way of saying that is that that a formula Φ is true iff in a model M its
interpretation I_[M,g ] (Φ) = 1 for all g:



I_[M] (Φ) = 1
iff
for all g, I_[M,g] (Φ) = 1
A formula Φ is valid iff it is true in all models:
I(Φ) = 1
iff
for all M, I_[M] (Φ) = 1
iff
for all M and g, I_[M,g] (Φ) = 1
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CA 208 Logic

With this we can now define/unpack the semantic consequence relation
|= for FOPL (in terms of validity I, truth I_[M] and interpretation I_[M,g] ...)

{P_1, ...., P_n} |= C
iff ((P_1  ....  P_n)  C) is valid
iff ((P_1  ....  P_n))  C is true in all models
iff the interpretation of ((P_1  ....  P_n)  C) is 1 for all models and
all variable assignment functions




In symbols:

{P_1, ...., P_n} |= C
iff
I((P_1  ....  P_n)  C) = 1 (i.e. formula is valid)
iff
I_[M] ((P_1  ....  P_n)  C) = 1 for all models M
iff
I_[M,g] ((P_1  ....  P_n)  C) = 1 for all models M and all variable
assignment functions g



51
CA 208 Logic

Do example model and some interpretations on
blackboard in class ...
52
CA 208 Logic




So what’s a model?
A model is always a model for a specific language, so
Given a FOPL language L with CONST = {j,k,m}, VAR = {x,y,z} and
П = {student¹, broke¹, like²}
Interpretation in a model: given our definition of the syntax and
semantics of First Order Predicate Logic (FOPL), and a (specific)
language of FOPL with CONST = {j,k,m}, VARS = {x,y,z} and
PRED = {student¹, broke¹, like²} and the following model M = <
U, > with U = {□, ◊, ○} and (j) = □, (m) = ◊, (k) = ○ ,
(student) = {□, ○}, (broke) = {□, ○} (like) =
{<□,□>,<○,□>,<◊,○>} and a variable assigment function g with
g(x) = ○, g(y)= ○, g(z)= ○, compute the truth value of the
following formulas relative to model M and variable assignment
function g (i.e. compute which of the following are satisfied in M
and g)?
53
CA 208 Logic Ex6

Interpretation in a model: given our definition of the syntax and semantics of First Order Predicate
Logic (FOPL), and a (specific) language of FOPL with CONST = {j,k,m}, VARS = {x,y,z} and PRED =
{student¹, broke¹, like²} and the following model M = < U, > with U = {□, ◊, ○} and (j) = □, (m) = ◊,
(k) = ○ , (student) = {□, ○}, (broke) = {□, ○} (like) = {<□,□>,<○,□>,<◊,○>} and a variable
assigment function g with g(x) = ○, g(y)= ○, g(z)= ○, compute the truth value of the following formulas
relative to model M and variable assignment function g (i.e. compute which of the following are
satisfied in M and g)?

like(j,j)
(like(j,j)  like(k,j))
like(j,k)
 x student(x)
 z student(z)
x student(x)
z student(z)
y broke(y)
x (student(x)  broke(x))
x (student(x)  broke(x))










Translate the FOPL formulas above into corresponding sentences in English (assume that j translates
to John, m to Mary and k to Kate while the predicate symbols translate into the corresponding English
verbs (like), nouns (student) and adjectives (broke)).
54
CA 208 Logic
Good things about the Natural Deduction calculus:




Easy to learn
Intutive account for each of the connectives
Close to how humans (mathemanticians ...) do proofs
ND rules can be used to define



Minimal Logic
Intuitionistic Logic
Classical Logic
Not so good things about Natural Deduction Calculus:



ND Proofs can require quite a bit of ingenuity and expertise
ND Proofs have non-local aspect (management of open intermediate premisses ...)
NP proofs can not easily be automated
Thats why we have other Calculi (Proof Systems) with are good for e.g. Automation of
Proofs ... Thats the subject of more advanced classes in Logic, Theorem Proving, AI,
...
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CA 208 Logic
What’s the relationship between |- and |=?


(P_1, ..., P_n) |- C
(P_1, ..., P_n) |= C
the syntactic consequence relation (ND proofs)
the semantic consequence relation (situations, truth tables ...)
For classical logics such as Propositional Logic we have that


(P_1, ..., P_n) |- C iff (P_1, ..., P_n) |= C
|- iff |=
i.e. anything (conclusion, theorem) that can be proved (in ND) is also a semantic consequence of the
same premises: if |- then |= (“soundness” of the calculus – here ND – i.e your proof rules are
good, they don’t produce rubbish)
And anything (conclusion, theorem) that is a sematic consequence of the some premises can also be
proved (with here ND) from the same premises (“completeness” of the calculus – here ND – i.e.
your proof rules allow to prove everything that can be proved)



|- iff |= = if |- than |= and if |= then |If |- then |= (Soundness)
If |= then |- (Completeness)
This is “metalogic” = looking at logic as a mathematical object and studying its properties. Soundness
and completeness proofs first given by Kurt Gödel. We don’t do that in this introduction to logic
here ……
56
CA 208 Logic
Propositional Logic as a Calculus: |[A]ass
:
B
------A→B
57