Transcript Powerpoint

EART 160: Planetary Science
Last Time
• HW 2 due Today
– How are people doing?
• Planetary Surfaces
– Volcanism
– Magma
– Volcanic Features on Planets
Today
• HW 2 due Today (for reals)
• Planetary Surfaces
– Tectonics
– Stress and Strain
– Faults and Folds
Tectonics
• Global tectonic patterns give us
information about a planet’s thermal
evolution
• Abundance and style of tectonic features
tell us how much, and in what manner, the
planet is being deformed
– How active is it?
• Some tectonic patterns arise because of
local loading (e.g. by volcanoes)
Modes of Deformation
• Extension
• Compression
• Shear
Extensional Tectonics
Valles Marineris, Mars (~8km deep)
Craters on Ganymede
37km diameter
Crater on Venus
Pappalardo & Collins 2005
Diam. appx 40km
Extension
• Extension accommodated by normal faulting
0
Stretching factor:
L0


L
L0

sin  0
sin 
L
• Fault blocks rotate as extension proceeds
• Typical normal faults start with dips of 60o and lock up
when dips=30o, giving stretching factor = 1.7
• Stretching factor also controls amount of subsidence that
happens during extension
A Martian Rift Valley
•Looks similar to terrestrial
continental rifts.
•Not been heavily studied, but
may provide useful insights
into crustal properties.
Hauber and Kronberg, JGR Planets, 2001
Graben Systems
15km
Steep scarp
Relay ramp?
across)
Canyonlands
graben, Utah,
2km across
Flat
floor
Graben, Ganymede
Bands (Europa)
20km
What drives the extension?
Sullivan et al., Nature (1998)
Compression
• Accomodated by reverse (or thrust) faulting
• Typical reverse faults start with dips of 30o
L0
0
L
Rarely Seen on Icy Satellites
Lots of Extension, No compression. How can this be?
The only example
of unambiguously
documented
compressional
features on
Europa to date
Prockter and Pappalardo, Science 2000
Wrinkle Ridges and Lobate Scarps
• Probably thrust faults at depth
(see cartoon)
• Found on Mars, Moon, Mercury,
Venus
• Possibly related to global
contraction due to cooling?
• Spacing may be controlled by
crustal structure
25 km
Krieger crater, Moon
50km
Mars, MOC wide-angle
Tate et al. LPSC 33, 2003
Io compressional tectonics
• Burial leads to large compressive stresses due to change in
radius
• Stresses easily large enough to
DR
initiate faulting
After McKinnon et al.,
• Additional compressive stresses may
arise from reheating the base of the crust Geology 2001
stereo
550 km
10km
Schenk and Bulmer, Science 1998
Low-angle thrust faulting is
probably responsible for
many of the mountain
ranges seen on Io
Strike-slip Motion
• Horizontal Movement
Right-Lateral
Left-Lateral
Europa, oblique strike-slip (image width 170km)
• Relatively rare (only seen on Earth & Europa)
• Associated with plate tectonic-like behaviour
Plate Tectonics
• Dominant style of
tectonics on Earth
• Unknown elsewhere
• Early Plate Tectonics
on Mars?
– (Sleep 1994, Nimmo &
Stevenson, 2000)
Stress
• Stresses are forces per unit area that are
transmitted through a material.
– Stresses transmitted perpendicular to a
surface are normal stresses
– Stresses transmitted parallel to a surface are
shear stresses
szz
s
xz
Strain
• Stress in an elastic solid results in
strain, or deformation of the solid
– Normal strain is the change in length
compared to the original length
– Shear strain is the change in
angle due to deformation.
wx
f1
dx‘
dx
exx = 1 - dx’/dx
f2
exz = -½ (f1 – f2)
Stress and Strain in Solids
 s xx s xy

s   s yx s yy
s
 zx s zy
• Stress and Strain are
Tensors (think of it as
a vector of vectors)
szz
syy
sxx
sxx
Maximum direction of principal
stress controls style of fault.
s xz 

s yz 

s zz 
syy
szz
Rheology
• Rheology is the study of the deformation
and flow of matter under the influence of
an applied stress
• If the deformation (or strain, e) follows the
stress, s, the material is elastic
– Returns to original state when stress is
released
• If the strain rate, de/dt follows the stress,
s, the material is viscous
Elastic
s
s0
sy
s  Ee
Failure Strength
Brittle Behavior
Yield
Strength
Plastic behavior
Viscous
s
s  e
e
e
E is the Young’s Modulus, or elasticity
is the viscosity
Analagous to the spring constant in
Hooke’s Law
Rarely a straight line plot in reality
Deformation
• You can think of Young’s modulus (units: Pa) as
the stress s required to cause a strain of 100%
• Typical values for geological materials are
– E = 100 GPa (rocks) and 10 GPa (ice)
–  = 1021 Pa s (rocks) 1014 Pa s (ice)
• HIGHLY Temperature, Pressure, Stress-dependent
• Elastic deformation is reversible; but if strains get too
large, material undergoes fracture (irreversible)
• Material may be both elastic AND viscous, depending on
the time-scale.
• We’ll talk more about this next week – Planetary
Interiors.
Mechanisms: Extension
• For icy satellites, one
possible explanation for the
ubiquitous extension is that
they possess floating ice
shells which thickened with
time (see below)
• Why should the shell thicken?
ice
water
Mechanisms: Compression
• Silicate planets frequently exhibit
compression (wrinkle ridges etc.)
• This is probably because the planets
have cooled and contracted over time
• Why do planets start out hot?
• Further contraction occurs when a liquid
core freezes and solidifies
• Contractional strain given by
Hot mantle
Liquid core
Cool mantle
e  DT
Where  is the thermal expansivity (3x10-5 K-1), DT is
the temperature change and the strain is the
fractional change in radius
Solid core
Tectonic Stresses & Byerlee’s law
• Byerlee’s law says that faults don’t
move unless the shear stress
fault
exceeds the normal stress times the
friction coefficient f
• For almost all geological materials,
f=0.6 (unless the fault is lubricated
somehow)
• In general, the normal stress is simply the overburden
pressure:
Shear stress
Normal
stress
Also applies to atmospheres!
P = rgh
• The shear stresses are provided by tectonic effects
• E.g. to cause a fault 10 km deep on Earth to move
requires tectonic stresses of 180 MPa (a lot!)
• Typical tectonic stresses on Earth are usually 10-100 MPa
Stress on a Fault
P = rgz
z

stec
sn
sn = Normal Stress
t = Shear Stress
P = Pressure (Lithostatic Stress)
t
Elastic Flexure
• The near-surface, cold parts of a planet (the
lithosphere) behaves elastically
• This lithosphere can support loads (e.g. volcanoes)
• We can use observations of how the lithosphere
deforms under these loads to assess how thick it is
• The thickness of the lithosphere tells us about how
rapidly temperature increases with depth i.e. it
helps us to deduce the thermal structure of the
planet
• The deformation of the elastic lithosphere under
loads is called flexure
• EART162: Planetary Surfaces
Flexural Stresses
load
Crust
Elastic plate
Mantle
• In general, a load will be supported by a
combination of elastic stresses and buoyancy forces
(due to the different density of crust and mantle)
• The elastic stresses will be both compressional and
extensional (see diagram)
• Note that in this example the elastic portion includes
both crust and mantle
Flexural Parameter
• Consider a load acting
on an elastic plate:
rw
load
rm
Te

• The plate has a particular elastic thickness Te
• If the load is narrow, then the width of deformation is
controlled by the properties of the plate
• The width of deformation  is called the flexural
parameter and is given by
   3g ( r

ETe3
m - r w )(1-
2

)
1
4
E is Young’s modulus, g is gravity and n is Poisson’s ratio (~0.3)
• If the applied load is much wider than , then the
load cannot be supported elastically and must be
supported by buoyancy (isostasy)
• If the applied load is much narrower than , then
the width of deformation is given by 
• If we can measure a flexural wavelength, that
allows us to infer  and thus Te directly.
• Inferring Te (elastic thickness) is useful because Te
is controlled by a planet’s temperature structure

Example
10 km
• This is an example of a profile
across a rift on Ganymede
• An eyeball estimate of  would
be about 10 km
• For ice, we take E=10 GPa,
Dr=900 kg m-3 (there is no
overlying ocean), g=1.3 ms-2
Distance, km
•
•
•
•
If =10 km then Te=1.5 km
A numerical solution gives Te=1.4 km – pretty good!
So we can determine Te remotely
This is useful because Te is ultimately controlled by the
temperature structure of the subsurface
Te and temperature structure
• Cold materials behave elastically
• Warm materials flow in a viscous fashion
• This means there is a characteristic temperature
(roughly 70% of the melting temperature) which
defines the base of the elastic layer
Depth
•E.g. for ice the base of the elastic layer 270 K
110 K
190 K
is at about 190 K
• The measured elastic layer thickness is
1.4 km
1.4 km (from previous slide)
elastic
• So the thermal gradient is 60 K/km
• This tells us that the (conductive) ice
viscous
shell thickness is 2.7 km (!)
Temperature
Te in the solar system
• Remote sensing observations give us Te
• Te depends on the composition of the material (e.g.
ice, rock) and the temperature structure
• If we can measure Te, we can determine the
temperature structure (or heat flux)
• Typical (approx.) values for solar system objects:
Body
Te (km)
Body
Te
30
dT/dz
(K/km)
15
Earth
(cont.)
Venus
(450oC)
30
Mars
(recent)
Europa
100
5
2
40
Moon
15
(ancient)
Ganymed 2
dT/dz
(K/km)
15
30
40
Next Time
• Paper Discussion
– Mars Crust and Mantle (Zuber et al., 2001)
– Io Volcanism (Spencer et al., 2007)
• Planetary Surfaces: Gradation
– Fluvial (Water)
– Aeolian (Wind)
– Glacial (Ice)
– Mass Wasting (Gravity)
– Sputtering (Charged Particles)