Transcript Section 1.7

CHAPTER 1: FUNCTIONS,
GRAPHS, AND MODELS; LINEAR
FUNCTIONS
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Section 1.7: Systems of Linear Equations in Two
Variables
SECTION 1.7: Systems of Linear
Equations in Two Variables
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The break even point is a term used to represent
the point at which the Revenue = Cost. (R(x) =
C(x))
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If we know R(x) and C(x), we can find the point at which
the functions ‘meet’ graphically.
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Graph both functions and identify the point of
intersection – this marks the break even point.
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SECTION 1.7: Systems of Linear
Equations in Two Variables

Suppose a company has its total revenue, in
dollars, for a product given by
R(x) = 5585x
and its total cost in dollars is given by
C(x) = 61,740 + 440x
where x is the number of thousands of tons of the
product that is produced and sold each year.
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Determine the break even point and the corresponding
values for R and C. Interpret.
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SECTION 1.7: Systems of Linear
Equations in Two Variables
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Let Y1 = R(x) and Y2 = C(x).
Graph both functions – be sure to use a window
that allows you to locate the intersection.
Find the point of intersection.
2nd TRACE (CALC)
 5: intersect
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Follow First and Second Curve Prompts (use the up and
down arrows to move from curve to curve)
Move the cursor to an approximate location for the guess.
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SECTION 1.7: Systems of Linear
Equations in Two Variables
Will two lines always intersect?
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If 2 equations graph the same line, we say the system is a
dependent system.
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If 2 equations graph parallel lines, we say the system is
inconsistent.
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There are an infinite number of solutions for such as system.
There is No solution for such a system.
If 2 equations graph with an intersection, we say the system is
consistent.
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There is one unique solution for such a system.
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SECTION 1.7: Systems of Linear
Equations in Two Variables
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Solution by Substitution
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Solve one of the equations for one of the variables in terms of
the other variable.
Substitute the expression from step 1 into the other equation
to give an equation in one variable.
Solve the linear equation for the variable.
Substitute this solution into the equation from step 1 or into
one of the original equations and solve this equation for the
second variable.
Check the solution in both original equations or check
graphically.
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SECTION 1.7: Systems of Linear
Equations in Two Variables

Solve the system below by substitution:
3x  4y  10

4x  2y  6
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SECTION 1.7: Systems of Linear
Equations in Two Variables

Solution by Elimination
If necessary, multiply one or both equations by a nonzero
number that will make the coefficients of one of the variables
in the equations equal, except perhaps for the sign.
 Add or subtract the equations to eliminate one of the
variables.
 Solve for the variable in the resulting equation.
 Substitute the solution from step 3 into one of the original
equations and solve for the second variable.
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Check the solutions in the remaining original equation, or
graphically.
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SECTION 1.7: Systems of Linear
Equations in Two Variables

Solve the system below by elimination:
3x  4y  10

4x  2y  6
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SECTION 1.7: Systems of Linear
Equations in Two Variables
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Market equilibrium
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Demand is the quantity of a product demanded by
consumers.
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Supply is the quantity of a product supplied .
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Both demand and supply are related to the price.
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Equilibrium price is the price at which the number of units
demanded equals the number of units supplied.
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We can also refer to this as market equilibrium.
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SECTION 1.7: Systems of Linear
Equations in Two Variables
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Suppose the daily demand for a product is given by
p = 200 – 2q, where q is the number of units
demanded and p is the price per unit dollars. The
daily supply is given by p = 60 + 5q, where q is the
number of units supplied and p is the price in
dollars.
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If the price is $140, how many units are supplied and how
many are demanded?
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Does this price result in a surplus or shortfall?
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What price gives market equilibrium?
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SECTION 1.7: Systems of Linear
Equations in Two Variables
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A nurse has two solutions that contain different
concentrations of certain medication. One is a 12%
concentration, and the other is an 8%
concentration. How many cubic centimeters (cc) of
each should she mix together to obtain 20cc of a
9% solution?
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SECTION 1.7: Systems of Linear
Equations in Two Variables
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An investor has $300,000 to invest, part at 12% and
the remainder in a less risky investment at 7%. If
her investment goal is to have an annual income of
$27,000, how much should she put in each
investment?
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SECTION 1.7: Systems of Linear
Equations in Two Variables
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Inconsistent and Dependent Systems
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Use elimination to solve each system, if possible.
2x  3 y  4

6 x  9 y  12
2x  3y  4

6x  9y  36
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SECTION 1.7: Systems of Linear
Equations in Two Variables
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Homework: pp. 110-114
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1-29 every other odd, 33, 37, 41, 45, 49, 53, 57
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