Transcript WWMD

Mendel’s Contribution(s)?
 Finish C. elegans experiment,
This Week
 Tinker with wasps,
 Exam Review (April 20th)
 Exam I (April 23rd),








Basic Mendel!
Basic Mendel!
Basic Mendel!
Basic Mendel!
Basic Mendel!
C. elegans!
Bioinfomatics!
Nasonia!
Mendel’s First Postulate
Unit Factors in Pairs
 Genetic characteristics are controlled by unit factors
that exist in pairs* in individual organisms,
 each individual receives one unit factor from each
parent*,
 in a monohybrid cross, three combinations of unit
factors are possible,
* not in Nasonia males!
Mendel’s Second Postulate
Dominant/Recessive
 When two unlike unit factors are present in a single
individual, one unit factor is dominant to the other,
which is said to be recessive.
Mendel’s Third Postulate
Segregation

During the processes of heredity, the paired unit
factors separate so that the offspring receives one
unit factor from each parent,

The unit factors segregate to offspring randomly.
Mendel’s Forth Postulate
Independent Assortment
 How do two traits segregate in the offspring of an
individual that is heterozygous for both traits?
Independent Assortment
…checking complementation in the F2
P:
AAdd x aaDD
P:
aadd x AADD
F1:
AaDd
F1:
AaDd
F2:
9: A_D_
F2:
9: A_D_
3: aaD_
3: aaD_
3: A_dd
3: A_dd
1: aadd
1: aadd
Both Recessive?
Both Dominant?
9:7 wt : mut
1:15 wt : mut
One of each?
3:13 wt : mut
P to F1
Haplo/Diplo: Thinking about complementation groups…
1. Both recessive:
aaDD x Ad  female: AaDd, male aD
2. Both Dominant: aaDD x Ad  female: AaDd, male aD
3. One dominant*: aadd x AD  female: AaDd, male ad
or…
AADD x ad  female: AaDd, male AD
* need to define which is dominant!
P to F1 to “F2”
Haplo/Diplo: Thinking about complementation groups…
1. Both recessive: aaDD x Ad  female: AaDd  ¼AD + ¼Ad + ¼aD + ¼ad
2. Both Dominant: aaDD x Ad  female: AaDd  ¼AD + ¼Ad + ¼aD + ¼ad
3. One dominant*: aadd x AD  female: AaDd  ¼AD + ¼Ad + ¼aD + ¼ad
or…
AADD x ad  female: AaDd  ¼AD + ¼Ad + ¼aD + ¼ad
* need to define which is dominant!
Forked-Line Method
Haplo/Diplo F2
AaDd x AD* (*male genotype could be ad, aD, Ad)
1/2 A
1/2 a
½D
1/2 x 1/2 = 1/4 AD
1 AD = ¼ AADD
½d
1/2 x 1/2 = 1/4 Ad
1 AD = ¼ AADd
1/2 D
1/2 x 1/2 = 1/4 aD
1 AD = ¼ AaDD
½d
1/2 x 1/2 = 1/4 ad
1 AD = ¼ AaDd
Forked-Line Method
Haplo/Diplo F2
AaDd x AD* (*male genotype could be ad, aD, Ad)
1/4 AD x 1 AD = ¼ AADD
1/4 AD x 1 ad = ¼ AaDd
1/4 Ad x 1 AD = ¼ AADd
1/4 Ad x 1 ad = ¼ Aadd
1/4 aD x 1 AD = ¼ AaDD
1/4 aD x 1 ad = ¼ aaDd
1/4 ad
x 1 AD = ¼ AaDd
1/4 ad
x 1 ad = ¼ aadd
Have Fun!
1/4 AD x 1 aD = ¼ AaDD
1/4 AD x 1 Ad = ¼ AADd
1/4 Ad x 1 aD = ¼ AaDd
1/4 Ad x 1 Ad = ¼ AAdd
1/4 aD x 1 aD = ¼ aaDD
1/4 aD x 1 Ad = ¼ aaDd
1/4 ad
x 1 aD = ¼ aaDd
1/4 ad
x 1 Ad = ¼ Aadd
Lab
Life Cycles
Wasp Development
Timelines
Life Cycles, Mating, etc.
C. elegans
Nomenclature
Tower of Babel
 Wednesday,
This Week
 score F3s,
 discuss Mendel Review
Formal Lab Write-Up,
 think about or tinker with
wasps?
 Friday,
 midterm,
 think about or tinker with
wasps?