1.4 Field analysis of transmission lines
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Transcript 1.4 Field analysis of transmission lines
Lecture 2
1.4 Field analysis of transmission lines
Derive the transmission line parameters (R, L, G, C) in
terms of the electromagnetic fields
Rederive the telegrapher equations using these parameters
Example:
Voltage : V0ejz
Current: I0ejz
Work (W) and power (P)
H* Multiplies the two sides of the first Maxell’s equation:
E Multiplies the two sides of the conjugated second Maxell’s equation:
Add the above two equations and utilize
We obtain (J=Js+σE):
Integrate the above formula in volume V and utilize divergence theory,
we have the following after reorganize the equation
Poynting law: PS Po Pl 2 j (Wm We )
Source power Ps: Ps
1
(
E
J
H
M s )dv
V
2
Output power P0: Po 1 E H d s 1 S d s
2 S
2 S
Loss power Pl:
Pl
2
(Time averaged)
V
2
E dv
( ' ' E
2
V
2
(S E H )
2
' ' H )dv
2
1
Stored magnetic energy Wm: Wm ' H dv
4 V
2
1
Stored electric energy We: We ' E dv
4 V
Calculate magnetic energy
Calculate the time-average stored magnetic energy in an isotropic medium ( the
results valid for any media )
1
Wm
2T
T
Re[ H ] Re[ B]dvdt
0V
1
2T
T
H cos(t ) B cos(t ) cos dtdv
1
2
V 0
1
H B cos cos(1 2 )dv
4V
1
Re H B dv
4 V
(cos eH eB )
( H H e j1 eH ;
B B e j2 eB )
Surface resistance and surface current of metal
Energy entering a conductor:
1
Pav Re E H nds
S0 S
2
The contribution to the integral from the surface S can be made zero by
proper selection of this surface. Therefore,
1
Pav Re E H t zds
S0
2
(H n E / )
From vector identity, we have z ( E H ) ( z E ) H H H .
The energy absorbed by a conductor:
Rs
Pav
2
S0
Rs
H t ds
2
2
S0
2
J s ds
( Rs Re( ) Re[(1 j )
Js n H )
1
]
2
s
1.4 Field analysis of transmission lines
Transmission line parameter: L
The time-average stored magnetic energy for 1 m
long transmission line is
Wm
4
H H ds
S
And circuit line gives W m L I 2 / 4 . Hence the self inductance could
be identified as
L
I0
2
H H
S
ds
( H / m)
Appendix 1:
Calculate the time-average stored magnetic energy in an isotropic medium ( the
results valid for any media )
1
Wm
2T
T
Re[ H ] Re[ B]dvdt
0V
1
2T
T
H cos(t ) B cos(t ) cos dtdv
1
2
V 0
1
H B cos cos(1 2 )dv
4V
1
Re H B dv
4 V
(cos eH eB )
( H H e j1 eH ;
B B e j2 eB )
1.4 Field analysis of transmission lines
Transmission line parameter: C
Similarly, the time-average stored electric energy per
unit length can be found as
We
E E ds
4
S
Circuit theory gives W e C V / 4, resulting in the following expression for the
capacitance per unit length:
2
C
V0
2
E E ds
S
( F / m)
1.4 Field analysis of transmission lines
Transmission line parameter: R
The power loss per unit length due to the finite
conductivity of the metallic conductors is
Rs
Pc
2
(Rs = 1/ is the surface resistance
and H is the tangential field)
H H dl
C1 C 2
The circuit theory gives P c R I 0 / 2 , so the series resistance R
per unit length of line is
2
R
Rs
I0
2
H H dl
C1 C 2
( / m)
1.4 Field analysis of transmission lines
Transmission line parameter, G
The time-average power dissipated per unit length in
a lossy dielectric is
Pd
' '
2
E E ds.
S
Circuit theory gives P d G V0 / 2 , so the shunt conductance
per unit length can be written as
2
G
' '
V0
2
E E ds
S
( S / m)
Homework
y
1. The fields of a traveling TEM wave inside the coaxial line shown left
can be expressed as
a
V0
I
E
e z ; H 0 e z
ln b / a
2
where is the propagation constant of the line. The conductors are
assumed to have a surface resistivity Rs, and the material filling the
space between the conductors is assumed to have a complex
permittivity = ’ - j" and a permeability μ = μ0μr. Determine the
transmission line parameters (L,C,R,G).
b
ρ
φ
x
μ,
y
w
2. For the parallel plate line shown left, derive the R, L, G, and C
parameters. Assume w >> d.
d
r
x
z