Distances between Data Sets Based on Summary Statistics

Download Report

Transcript Distances between Data Sets Based on Summary Statistics

Machine Learning Paper Reading Series
Distances between Data Sets Based
on Summary Statistics
Nikolaj Tatti, JMLR, 01/2007
Presented by Yuting Qi
ECE Dept.
Duke Univ.
02/02/2007
Introduction
• Goal:
– Define a dissimilarity measure, the constrained
minimum (CM) distance, between two data sets
D1 and D2 by comparing summary statistics of
datasets.
• Requirements:
– It should be a metric.
– It should consider the statistical nature of data.
– It should be evaluated quickly.
The Constrained Minimum (CM) Distance
1/5
• Definition:
– Basic notations:
•
•
•
•
D: data set, a finite collection of samples in Ω.
Ω: finite sample space, |Ω| is the # of elements in Ω.
S: feature function,
, known or learned.
Θ: frequency,
, the average values of S over D,
S(D)
Example:
Ω={A,B,C}, D1=(C,C,C,A), D2=(C,A,B,A)
The only feature of interest is the proportion of C in the data set,
then the feature function S is
S(D1)=3/4, S(D2)=1/4
The Constrained Minimum (CM) Distance
2/5
– Constrained set of distributions:
P is the set of all distributions defined on Ω.
Calculated from given data sets
We estimate statistics from given data set, then examine
the distributions that can produce such statistics.
– An alternative definition of
:
If think Ω={1,2,…,|Ω|}, P is a set of vectors, u, in R|Ω| satisfying
non-negative elements and summing to 1.
ui=p(i)
– Constrained space:
Given θ1 and θ2,
//
The Constrained Minimum (CM) Distance
3/5
• Illustration:
Example:
Ω={A,B,C}, D1=(C,C,C,A), D2=(C,A,B,A)
the feature function S is
S(D1)=0.75, S(D2)=0.25
P is the triangle,
is a plane
Then, C(S, 0.75), C(S, 0.25) are parallel lines
The constrained set of distributions
C
C+(S, 0.75), C+(S, 0.25) are the segments
Motivate:
A nature way to measure the distance between
two parallel spaces: find the shortest length
from two points from each space.
A
B
The Constrained Minimum (CM) Distance
• CM Distance
– Pick a vector from each constrained space
– CM distance between D1 and D2 is
• Theorem 1
• Computation time:
–
– |Ω| could be very large, O(N3) time is feasible
4/5
The Constrained Minimum (CM) Distance
• Properties:
5/5
CM Distance and Binary Data Sets
1/2
• Basic definitions:
– Sample space:
– Itemset:
, ai corresponds to ith dimension.
– Boolean formula S: Ω->{0,1}
• Conjunction function SB:
– SB(w)=wi1^wi2^…^wiL, given itemset B={ai1, …, aiL}
• Parity function TB:
– TB(w)=wi1+wi2+…+wiL (+: XOR)
– Given a collection of itemsets F={B1,…, BN}, we have
CM Distance and Binary Data Sets
2/2
• CM distance can be calculated in O(N) time
assuming know θ1 and θ2.
CM Distance and Event Sequences
1/1
• Transform a sequence s to a binary data set
Given a window length k, pick a window in s and
transform it into a binary vector of length |Ω|
(the alphabet) by setting 1 if the corresponding
symbol occurs in window. S->D
• Define a way F to represent the statistics of
sequence s, popular choice is episodes.
• Given transformed data sets D1, D2, F, the
CM distance between s1 and s2 is
Empirical Tests
• 7 datasets:
– Bible, Addresses, Beatles, 20Newsgroups,
TopGenres, TopDecades, Abstact
– Compare CM distance to a base distance
– Clustering experiments using different algorithms
based on CM distance.
Empirical Tests
Conclusions & Discussion
• CM distance has nice statistical properties
and can be evaluated efficiently
• It takes properly into account the correlation
between features
• For many types of feature functions, the
computation time of CM distance is fast.
• The performance of CM distance depends
heavily on the data set.