Transcript Lecture 11

Exam II
Physics 101: Lecture 11
Momentum and Impulse

Today’s lecture will cover Textbook Sections 7.1-7.5
Physics 101: Lecture 9, Pg 1
Key Ideas

Last Time: Work-Energy
S F = m a
multiply both sides by d
S F d= m a d (note a d = ½ Dv2)
S F d= ½ m Dv2
S W = DKE
Define Work and Kinetic Energy

This Time: Impulse-Momentum
S F = m a
multiply both sides by Dt
S F Dt= m a Dt (note a Dt = Dv)
S F Dt= m Dv
S I = Dp
Define Impulse and Momentum
Physics 101: Lecture 9, Pg 2
08
ACT
Two identical balls are dropped from the same height onto the
floor. In each case they have velocity v downward just before
hitting the floor. In case 1 the ball bounces back up, and in
case 2 the ball sticks to the floor without bouncing. In which
case is the magnitude of the impulse given to the ball by the
floor the biggest?
A. Case 1
correct
B. Case 2
Bouncing Ball
Sticky Ball
C. The same
|I| = |Dp|
|I| = |Dp|
Vi = -5 m/s
Vf = +5 m/s
= |mvfinal – m vinitial|
= |mvfinal – m vinitial|
= |m( vfinal-vinitial)|
= |m( 0-vinitial)|
=2mv
= mv
Physics 101: Lecture 9, Pg 3
16
ACT
In both cases of the above question, the
direction of the impulse given to the ball by the
floor is the same. What is this direction?
A. Upward
correct
B. Downward
time
Physics 101: Lecture 9, Pg 4
19
ACTs
You drop an egg onto 1) the floor 2) a thick
piece of foam rubber. In both cases, the egg
does not bounce.
In which case is the impulse greater?
A) Floor
B) Foam
I = DP
Same change in momentum
C) the same
In which case is the average force greater
A) Floor
B) Foam
C) the same
Dp = F Dt
F = Dp/Dt
Smaller Dt = large F
Physics 101: Lecture 9, Pg 5
24
Pushing Off…
Fred (75 kg) and Jane (50 kg) are at rest on skates facing each
other. Jane then pushes Fred w/ a constant force F = 45 N for a
time Dt=3 seconds. Who will be moving fastest at the end of
the push?
A) Fred
B) Same
C) Jane
Fred
Jane
F = +45 N (positive direct.)
F = -45 N Newton’s 3rd law
I = +45 (3) N-s = 135 N-s
I = -45 (3) N-s = -135 N-s
I = Dp
I = Dp
= mvf – mvi
= mvf – mvi
I/m = vf - vi
I/m = vf - vi
vf = 135 N-s / 75 kg
vf = -135 N-s / 50 kg
= 1.8 m/s
= -2.7 m/s
Note: Pfred + Pjane = (1.8) 75 + (-2.7) 50
= Physics
0! 101: Lecture 9, Pg 6
29
Momentum is Conserved
 Momentum
is “Conserved” meaning
it can not be created nor destroyed
Can be transferred
 Total
Momentum does not change
with time.
This
is a BIG deal!
Physics 101: Lecture 9, Pg 7
30
Impulse and Momentum
Summary
FaveDt  I = pf - pi = Dp

For single object….
F = 0  momentum conserved (Dp = 0)

For collection of objects …
 SFext = 0  total momentum conserved (DPtot = 0)
 Fext = mtotal a
Physics 101: Lecture 9, Pg 8
33
Momentum ACT
A car w/ mass 1200 kg is driving north at 40 m/s, and turns
east driving 30 m/s. What is the magnitude of the car’s change
in momentum?
A) 0 B) 12,000
C) 36,000
D) 48,000
E) 60,000
Pinitial = m vinitial = (1200 Kg) x 40 m/s = 48,000 kg m/s North
Pfinal = m vfinal = (1200 Kg) x 30 m/s = 36,000 kg m/s East
North-South:
Pfinal – Pinitial = (0 – 48000) = -48,000 kg m/s
30 m/s
East-West:
Pfinal – Pinitial = (36000 - 0) = +36,000 kg m/s
40 m/s
Magnitude :
Sqrt(P2North – P2East ) = 60,000 kg m/s
Physics 101: Lecture 9, Pg 9
38
Preflight 2 & 3
Is it possible for a system of two objects to have zero total
momentum while having a non-zero total kinetic energy?
63%
1. YES
37%
2. NO
correct
62%
“astornaut and shuttle”
38%
0%
20%
40%
60%
80%
“If the velocity of one object is positive and the velocity of the other object
is negative you can have a momentum of 0 but because the total kinetic
energy is 1/2mv^2 the negative velocity because a positive one giving
therefore resulting in a non-zero total kinetic energy.”
“If the Object has a non zero kinetic energy, it is moving, therefore it
has momentum.”
Physics 101: Lecture 9, Pg 10 41
ACT
Movies often show someone firing a gun loaded with
blanks. In a blank cartridge the lead bullet is removed
and the end of the shell casing is crimped shut to
prevent the gunpowder from spilling out. When a gun
fires a blank, is the recoil greater than, the same as, or
less than when the gun fires a standard bullet?
A. greater than
B. same as
C. less than
correct
pgun = -pbullet
If there is no bullet then pbullet = 0 so pgun = 0
As if ice skater had no one to push…
Physics 101: Lecture 9, Pg 11 48
Summary
Impulse I = FDt
» Gives change in momentum I = Dp
Momentum p = mv
» Momentum is VECTOR
» Momentum is conserved (when SF = 0)
 S mvinitial = S mvfinal
Chapter 7, problems 3, 5, 13, 21
Physics 101: Lecture 9, Pg 12 50