Transcript Lecture_19

Chapter 16
Sound
Copyright © 2009 Pearson Education, Inc.
ConcepTest 16.6c Pied Piper III
If you blow across the opening
of a partially filled soda bottle,
you hear a tone. If you take a big
sip of soda and then blow
across the opening again, how
will the frequency of the tone
change?
1) frequency will increase
2) frequency will not change
3) frequency will decrease
ConcepTest 16.6c Pied Piper III
If you blow across the opening
of a partially filled soda bottle,
you hear a tone. If you take a big
sip of soda and then blow
across the opening again, how
will the frequency of the tone
change?
1) frequency will increase
2) frequency will not change
3) frequency will decrease
By drinking some of the soda, you have effectively increased the
length of the air column in the bottle. A longer pipe means that
the standing wave in the bottle would have a longer wavelength.
Because the wave speed remains the same, and we know that
v = f l, then we see that the frequency has to be lower.
Follow-up: Why doesn’t the wave speed change?
ConcepTest 16.9 Interference
Speakers A and B emit sound
waves of l = 1 m, which
interfere constructively at a
donkey located far away (say,
200 m). What happens to the
sound intensity if speaker A is
moved back 2.5 m?
1) intensity increases
2) intensity stays the same
3) intensity goes to zero
4) impossible to tell
A
B
L
ConcepTest 16.9 Interference
Speakers A and B emit sound
waves of l = 1 m, which
interfere constructively at a
donkey located far away (say,
200 m). What happens to the
sound intensity if speaker A
steps back 2.5 m?
1) intensity increases
2) intensity stays the same
3) intensity goes to zero
4) impossible to tell
If l = 1 m, then a shift of 2.5 m corresponds to 2.5l, which
puts the two waves out of phase, leading to destructive
interference. The sound intensity will therefore go to
zero.
A
Follow-up: What if you
move back by 4 m?
B
L
16-7 Doppler Effect
The Doppler effect occurs when a source of
sound is moving with respect to an observer.
A source moving toward an observer appears
to have a higher frequency and shorter
wavelength; a source moving away from an
observer appears to have a lower frequency
and longer wavelength.
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16-7 Doppler Effect
Emitted at t  T
t 0

If we can figure out
what the change in
the wavelength is,
we also know the
change in the
frequency.
l  v sT  l '
v vs v
 
f
f
f'
1
v
  v  vs  
f
f'

t T
 v 

1 
 f '
 f 
f
 v  vs 
 1  vs v 
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16-7 Doppler Effect
The change in the frequency is given by:
If the source is moving away from the
observer:
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16-7 Doppler Effect
If the observer is moving with respect to the
source, things are a bit different. The
wavelength remains the same, but the wave
speed is different for the observer.
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16-7 Doppler Effect
We find, for an observer moving toward a
stationary source:
And if the observer is moving away:
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16-7 Doppler Effect
Example 16-14: A moving siren.
The siren of a police car at rest emits at a
predominant frequency of 1600 Hz. What
frequency will you hear if you are at rest and
the police car moves at 25.0 m/s (a) toward
you, and (b) away from you?
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16-7 Doppler Effect
Example 16-15: Two
Doppler shifts.
A 5000-Hz sound wave is
emitted by a stationary
source. This sound wave
reflects from an object
moving toward the source.
What is the frequency of
the wave reflected by the
moving object as detected
by a detector at rest near
the source?
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16-7 Doppler Effect
All four equations for the Doppler effect
can be combined into one; you just have to
keep track of the signs!
Basic point:
if source and receiver moving closer – f’ > f
if source and receiver moving apart – f’ < f
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ConcepTest 16.11a Doppler Effect I
Observers A, B, and C listen to a
moving source of sound. The
location of the wave fronts of the
moving source with respect to
the observers is shown below.
Which of the following is true?
1) frequency is highest at A
2) frequency is highest at B
3) frequency is highest at C
4) frequency is the same at all
three points
ConcepTest 16.11a Doppler Effect I
Observers A, B, and C listen to a
moving source of sound. The
location of the wave fronts of the
moving source with respect to
the observers is shown below.
Which of the following is true?
1) frequency is highest at A
2) frequency is highest at B
3) frequency is highest at C
4) frequency is the same at all
three points
The number of wave fronts
hitting observer C per unit time
is greatest—thus the observed
frequency is highest there.
Follow-up: Where is the frequency lowest?
16-8 Shock Waves and the Sonic Boom
If a source is moving faster than the wave
speed in a medium, waves cannot keep up and
a shock wave is formed.
The angle of the cone is:
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Chapter 31
Maxwell’s Equations and
Electromagnetic Waves
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Units of Chapter 31
• Changing Electric Fields Produce Magnetic
Fields; Ampère’s Law and Displacement
Current
• Gauss’s Law for Magnetism
• Maxwell’s Equations
• Production of Electromagnetic Waves
• Electromagnetic Waves, and Their Speed,
Derived from Maxwell’s Equations
• Light as an Electromagnetic Wave and the
Electromagnetic Spectrum
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Units of Chapter 31
• Measuring the Speed of Light
• Energy in EM Waves; the Poynting Vector
• Radiation Pressure
• Radio and Television; Wireless
Communication
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E&M Equations to date
Gauss' Law:
 E  dA 
Qenc
0
dB
Faraday's Law:  E  d  
dt
Ampere's Law:
 Bd
 0 I enc
Two for the electric field;
only one for the magnetic
field – not very symmetric!
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ConcepTest 31.1a
A loop with an AC current produces
a changing magnetic field. Two
loops have the same area, but one
is made of plastic and the other
copper. In which of the loops is
the induced voltage greater?
EM Waves I
1) the plastic loop
2) the copper loop
3) voltage is same in both
Plastic
Copper
ConcepTest 31.1a
A loop with an AC current produces
a changing magnetic field. Two
loops have the same area, but one
is made of plastic and the other
copper. In which of the loops is
the induced voltage greater?
Faraday’s law says nothing about
the material:
d
%  N
B
dt
The change in flux is the same (and
N is the same), so the induced emf
is the same.
EM Waves I
1) the plastic loop
2) the copper loop
3) voltage is same in both
Plastic
Copper
31-2 Gauss’s Law for Magnetism
Gauss’s law relates the electric field on a
closed surface to the net charge enclosed
by that surface. The analogous law for
magnetic fields is different, as there are no
single magnetic point charges
(monopoles):
Qmag  0 
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mag
B

dA



Q
0 enc  0

E&M Equations to date - updated
 E  dA 
Qenc
0
mag
B

dA



Q
0 enc  0

dB
 E  d   dt
 Bd
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 0 I enc
E&M Equations to date - updated
 E  dA 
Qenc
0
mag
B

dA



Q
0 enc

No effect since RHS
identically zero
dB
 E  d   dt

 Bd

 0 I enc
dQ
dQ mag
mag
Now, I 
suggests I 
0
dt
dt
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These two not pretty,
i.e., not symmetric
E&M Equations to date – more
updated
 E  dA 
Qenc
0
mag
B

dA



Q
0 enc

mag
d  B I enc
 E  d   dt   0
 Bd

???  0 I enc
Wouldn’t it be nice if we could replace ??? with something?
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31-1 Changing Electric Fields
Produce Magnetic Fields; Ampère’s
Law and Displacement Current
Ampère’s law
relates the
magnetic field
around a current
to the current
through a
surface.
 Bd
 0 I encl
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31-1 Changing Electric Fields Produce
Magnetic Fields; Ampère’s Law and
Displacement Current
In order for Ampère’s
law to hold, it can’t
matter which surface
we choose. But look
at a discharging
capacitor; there is a
current through
surface 1 but none
through surface 2:
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31-1 Changing Electric Fields
Produce Magnetic Fields; Ampère’s
Law and Displacement Current
Therefore, Ampère’s law is modified to include
the creation of a magnetic field by a changing
electric field – the field between the plates of the
capacitor in this example:
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31-1 Changing Electric Fields
Produce Magnetic Fields; Ampère’s
Law and Displacement Current
Example 31-1: Charging capacitor.
A 30-pF air-gap capacitor has circular plates of area
A = 100 cm2. It is charged by a 70-V battery through a
2.0-Ω resistor. At the instant the battery is connected,
the electric field between the plates is changing most
rapidly. At this instant, calculate (a) the current into
the plates, and (b) the rate of change of electric field
between the plates. (c) Determine the magnetic field
induced between the plates. Assume E is uniform
between the plates at any instant and is zero at all
points beyond the edges of the plates.
Copyright © 2009 Pearson Education, Inc.
31-1 Changing Electric Fields
Produce Magnetic Fields; Ampère’s
Law and Displacement Current
The second term in Ampere’s law has the
dimensions of a current (after factoring out
the μ0), and is sometimes called the
displacement current:
where
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31-3 Maxwell’s Equations
We now have a complete set of equations
that describe electric and magnetic fields,
called Maxwell’s equations. In the absence of
dielectric or magnetic materials, they are:
Qenc
 E  dA 
0
mag
B

dA



Q
0 enc

d  B I emag
nc
E

d




dt
0
dE
 B  d  0 0 dt  0 I enc
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31-4 Production of Electromagnetic
Waves
Since a changing electric field produces
a magnetic field, and a changing
magnetic field produces an electric field,
once sinusoidal fields are created they
can propagate on their own.
These propagating fields are called
electromagnetic waves.
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31-4 Production of Electromagnetic
Waves
Oscillating charges
will produce
electromagnetic
waves:
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31-4 Production of Electromagnetic
Waves
Close to the antenna,
the fields are
complicated, and are
called the near field:
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31-4 Production of Electromagnetic
Waves
Far from the source, the waves
are plane waves:
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31-4 Production of Electromagnetic
Waves
The electric and magnetic waves are
perpendicular to each other, and to the
direction of propagation.
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31-5 Electromagnetic Waves, and
Their Speed, Derived from Maxwell’s
Equations
In the absence of currents and charges,
Maxwell’s equations become:
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31-5 Electromagnetic Waves, and
Their Speed, Derived from Maxwell’s
Equations
This figure shows an electromagnetic wave of
wavelength λ and frequency f. The electric and
magnetic fields are given by
.
where
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31-5 Electromagnetic Waves, and
Their Speed, Derived from Maxwell’s
Equations
Applying Faraday’s law to the rectangle of
height Δy and width dx in the previous figure
gives a relationship between E and B:
.
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31-5 Electromagnetic Waves, and
Their Speed, Derived from Maxwell’s
Equations
Similarly, we apply
Maxwell’s fourth
equation to the
rectangle of length Δz
and width dx, which
gives
.
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31-5 Electromagnetic Waves, and
Their Speed, Derived from Maxwell’s
Equations
Using these two equations and the
equations for B and E as a function of time
gives
.
Here, v is the velocity of the wave.
Substituting,
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31-5 Electromagnetic Waves, and
Their Speed, Derived from Maxwell’s
Equations
The magnitude of this speed is
3.0 x 108 m/s – precisely equal
to the measured speed of light.
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31-6 Light as an Electromagnetic Wave
and the Electromagnetic Spectrum
The frequency of an electromagnetic wave
is related to its wavelength and to the
speed of light:
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31-5 Electromagnetic Waves, and
Their Speed, Derived from Maxwell’s
Equations
Example 31-2: Determining E and B in EM
waves.
Assume a 60-Hz EM wave is a sinusoidal
wave propagating in the z direction with E
pointing in the x direction, and E0 = 2.0 V/m.
Write vector expressions for E and B as
functions of position and time.
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31-6 Light as an Electromagnetic Wave
and the Electromagnetic Spectrum
Electromagnetic waves can have any
wavelength; we have given different names to
different parts of the wavelength spectrum.
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31-6 Light as an Electromagnetic Wave
and the Electromagnetic Spectrum
Example 31-3: Wavelengths of EM waves.
Calculate the wavelength
(a) of a 60-Hz EM wave,
(b) of a 93.3-MHz FM radio wave, and
(c) of a beam of visible red light from a
laser at frequency 4.74 x 1014 Hz.
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31-6 Light as an Electromagnetic Wave
and the Electromagnetic Spectrum
Example 31-4: Cell phone antenna.
The antenna of a cell phone is often ¼
wavelength long. A particular cell phone has
an 8.5-cm-long straight rod for its antenna.
Estimate the operating frequency of this
phone.
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ConcepTest 31.2
Oscillations
1) in the north-south plane
The electric field in an EM
wave traveling northeast
oscillates up and down. In
what plane does the
magnetic field oscillate?
2) in the up-down plane
3) in the NE-SW plane
4) in the NW-SE plane
5) in the east-west plane
ConcepTest 31.2
Oscillations
1) in the north-south plane
The electric field in an EM
wave traveling northeast
oscillates up and down. In
what plane does the
magnetic field oscillate?
2) in the up-down plane
3) in the NE-SW plane
4) in the NW-SE plane
5) in the east-west plane
The magnetic field oscillates perpendicular to BOTH the
electric field and the direction of the wave. Therefore the
magnetic field must oscillate in the NW-SE plane.