Ch. 6 MC Review

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Transcript Ch. 6 MC Review

Active Learning Lecture Slides
For use with Classroom Response Systems
Chapter 6: Probability Distributions
Statistics: The Art and
Science of Learning from
Data
Second Edition
by Agresti/Franklin
6.1.1) All students in a class were asked how many
times they had read the city newspaper in the past 5
days. The data is in the chart below. What proportion
read the newspaper more than 3 times in the past 5
days?
a)
b)
c)
d)
e)
0.1
0.5
0.6
1.0
None of the above
No. Times
Read
Newspaper
Probability
0
0.25
1
0.05
2
0.10
3
0.10
4
0.15
5
0.35
Copyright © 2009 Pearson Education
6.1.1) All students in a class were asked how many
times they had read the city newspaper in the past 5
days. The data is in the chart below. What proportion
read the newspaper more than 3 times in the past 5
days?
a)
b)
c)
d)
e)
0.1
0.5
0.6
1.0
None of the above
No. Times
Read
Newspaper
Probability
0
0.25
1
0.05
2
0.10
3
0.10
4
0.15
5
0.35
Copyright © 2009 Pearson Education
6.1.2) All students in a class were asked how
many times they had read the city newspaper in
the past 5 days. The data is in the chart below.
What is the expected number of times that
someone will have read the newspaper in the past
5 days?
No. Times
Probability
a)
b)
c)
d)
e)
2.5
2.9
3
3.9
None of the above
Read
Newspaper
0
0.25
1
0.05
2
0.10
3
0.10
4
0.15
5
0.35
Copyright © 2009 Pearson Education
6.1.2) All students in a class were asked how
many times they had read the city newspaper in
the past 5 days. The data is in the chart below.
What is the expected number of times that
someone will have read the newspaper in the past
5 days?
No. Times
Probability
a)
b)
c)
d)
e)
2.5
2.9
3
3.9
None of the above
Read
Newspaper
0
0.25
1
0.05
2
0.10
3
0.10
4
0.15
5
0.35
Copyright © 2009 Pearson Education
6.1.3) Suppose there is a special new lottery in your
state. Each lottery ticket is worth $20 and gives you
a chance at being selected to win $2,000,000. There
is a 0.0001% chance that you will be selected and
win otherwise, you win nothing. Let X denote your
winnings. What is the expected value of X?
a)
b)
c)
d)
e)
$2
$0
$2,000,000
$1,999,980
$200
Copyright © 2009 Pearson Education
6.1.3) Suppose there is a special new lottery in your
state. Each lottery ticket is worth $20 and gives you
a chance at being selected to win $2,000,000. There
is a 0.0001% chance that you will be selected and
win otherwise, you win nothing. Let X denote your
winnings. What is the expected value of X?
a)
b)
c)
d)
e)
$2
$0
$2,000,000
$1,999,980
$200
Copyright © 2009 Pearson Education
6.1.4) Suppose that a random number generator
can generate any number, including decimals,
between 0 and 10 with any value being equally
likely to be chosen. What is the probability that a
number is drawn between 7 and 10?
a)
b)
c)
d)
e)
0.4
0.3
0.2
0.1
0.273
Copyright © 2009 Pearson Education
6.1.4) Suppose that a random number generator
can generate any number, including decimals,
between 0 and 10 with any value being equally
likely to be chosen. What is the probability that a
number is drawn between 7 and 10?
a)
b)
c)
d)
e)
0.4
0.3
0.2
0.1
0.273
Copyright © 2009 Pearson Education
6.1.5) Suppose that a random number generator
can generate any number, including decimals,
between 0 and 10 with any value being equally
likely to be chosen. What would be the mean of
this distribution?
a)
b)
c)
d)
e)
4.5
5
5.5
6
Cannot be determined
Copyright © 2009 Pearson Education
6.1.5) Suppose that a random number generator
can generate any number, including decimals,
between 0 and 10 with any value being equally
likely to be chosen. What would be the mean of
this distribution?
a)
b)
c)
d)
e)
4.5
5
5.5
6
Cannot be determined
Copyright © 2009 Pearson Education
6.2.1) Which of the following is NOT a property of
the normal distribution?
a)
b)
c)
d)
e)
It is symmetric.
It is bell-shaped.
It is centered at the mean, 0.
It has a standard deviation, σ.
All of the above are correct.
Copyright © 2009 Pearson Education
6.2.1) Which of the following is NOT a property of
the normal distribution?
a)
b)
c)
d)
e)
It is symmetric.
It is bell-shaped.
It is centered at the mean, 0.
It has a standard deviation, σ.
All of the above are correct.
Copyright © 2009 Pearson Education
6.2.2) Scores on the verbal section of the SAT
have a mean of 500 and a standard deviation of
100. What proportion of SAT scores are higher
than 450?
a)
b)
c)
d)
e)
0.5
0.5557
0.6915
0.3085
0.7257
Copyright © 2009 Pearson Education
6.2.2) Scores on the verbal section of the SAT
have a mean of 500 and a standard deviation of
100. What proportion of SAT scores are higher
than 450?
a)
b)
c)
d)
e)
0.5
0.5557
0.6915
0.3085
0.7257
Copyright © 2009 Pearson Education
6.2.3) Scores on the verbal section of the SAT
have a mean of 500 and a standard deviation of
100. If someone scored at the 90th percentile, what
is their SAT score?
a)
b)
c)
d)
e)
608
618
628
638
648
Copyright © 2009 Pearson Education
6.2.3) Scores on the verbal section of the SAT
have a mean of 500 and a standard deviation of
100. If someone scored at the 90th percentile, what
is their SAT score?
a)
b)
c)
d)
e)
608
618
628
638
648
Copyright © 2009 Pearson Education
6.2.4) What is the standard normal distribution?
a)
b)
c)
d)
e)
N(μ, σ)
N(σ, μ)
N(1,0)
N(0,1)
N(-z, z)
Copyright © 2009 Pearson Education
6.2.4) What is the standard normal distribution?
a)
b)
c)
d)
e)
N(μ, σ)
N(σ, μ)
N(1,0)
N(0,1)
N(-z, z)
Copyright © 2009 Pearson Education
6.2.5) There are two sections of Intro Statistics and
they both gave an exam on the same material.
Suppose that Megan made an 83 in 2nd period and
Jose’ made an 85 in
3rd period. Using the
information below. Who scored relatively higher with
respect to their own period?
a)
b)
c)
d)
2nd period
3rd period
Mean
80
82
Standard Deviation
5
6
Jose’
Megan
They are the same.
Cannot be determined.
Copyright © 2009 Pearson Education
6.2.5) There are two sections of Intro Statistics and
they both gave an exam on the same material.
Suppose that Megan made an 83 in 2nd period and
Jose’ made an 85 in
3rd period. Using the
information below. Who scored relatively higher with
respect to their own period?
a)
b)
c)
d)
2nd period
3rd period
Mean
80
82
Standard Deviation
5
6
Jose’
Megan
They are the same.
Cannot be determined.
Copyright © 2009 Pearson Education
6.3.1) Which of the following is NOT a condition of
the binomial distribution?
a) The trials are dependent.
b) There are a set number of trials, n.
c) The probability of success is constant from trial
to trial.
d) There are two possible outcomes.
Copyright © 2009 Pearson Education
6.3.1) Which of the following is NOT a condition of
the binomial distribution?
a) The trials are dependent.
b) There are a set number of trials, n.
c) The probability of success is constant from trial
to trial.
d) There are two possible outcomes.
Copyright © 2009 Pearson Education
6.3.2) Suppose that you flipped an unbalanced
coin 10 times. Suppose that the probability of
getting “heads-up” was 0.3 and that X equals the
number of times that you get “heads-up”. If X has a
binomial distribution, what is the probability that X
= 4?
a)
b)
c)
d)
0.20
0.25
0.30
0.50
Copyright © 2009 Pearson Education
6.3.2) Suppose that you flipped an unbalanced
coin 10 times. Suppose that the probability of
getting “heads-up” was 0.3 and that X equals the
number of times that you get “heads-up”. If X has a
binomial distribution, what is the probability that X
= 4?
a)
b)
c)
d)
0.20
0.25
0.30
0.50
Copyright © 2009 Pearson Education
6.3.3) Suppose that you flipped an unbalanced
coin 10 times. Suppose that the probability of
getting “heads-up” was 0.3 and that X equals the
number of times that you get “heads-up”. If X has a
binomial distribution, what is the expected value
and standard deviation of X?
a)
b)
c)
d)
e)
Expected value = 3
Expected value = 3
Expected value = 0.3
Expected value = 0.3
Expected value = 3
Standard Deviation = 2.1
Standard Deviation = .145
Standard Deviation = .145
Standard Deviation = 1.45
Standard Deviation = 1.45
Copyright © 2009 Pearson Education
6.3.3) Suppose that you flipped an unbalanced
coin 10 times. Suppose that the probability of
getting “heads-up” was 0.3 and that X equals the
number of times that you get “heads-up”. If X has a
binomial distribution, what is the expected value
and standard deviation of X?
a)
b)
c)
d)
e)
Expected value = 3
Expected value = 3
Expected value = 0.3
Expected value = 0.3
Expected value = 3
Standard Deviation = 2.1
Standard Deviation = .145
Standard Deviation = .145
Standard Deviation = 1.45
Standard Deviation = 1.45
Copyright © 2009 Pearson Education
6.3.4) Suppose that a college level basketball
player has an 80% chance of making a free throw.
Suppose that he shoots 8 free throws in a game.
What is his expected number of baskets?
a)
b)
c)
d)
0.8
1
6.4
7.2
Copyright © 2009 Pearson Education
Copyright © 2009 Pearson Education
6.3.5) Suppose that a college level basketball
player has an 80% chance of making a free throw.
Suppose that he shoots 8 free throws in a game.
What is the probability that he makes 7 baskets?
a)
b)
c)
d)
e)
0.042
0.167
0.294
0.336
0.80
Copyright © 2009 Pearson Education
Copyright © 2009 Pearson Education
6.3.5) Suppose that a college level basketball
player has an 80% chance of making a free throw.
Suppose that he shoots 8 free throws in a game.
What is the probability that he makes 7 baskets?
a)
b)
c)
d)
e)
0.042
0.167
0.294
0.336
0.80
Copyright © 2009 Pearson Education
Copyright © 2009 Pearson Education