Transcript graph 35

One Day
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A system of linear equations is simply two or
more linear equations using the same
variables.
If the system of linear equations has a
solution, then the solution will be an ordered
pair (x, y) where x and y make both equations
true at the same time.
We will be dealing with systems of 2 equations
with 2 variables as well as systems that have 3
equations and 3 variables (x, y, z).
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Consider the following system:
 x  y  1

x  2 y  5
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y
 y  x 1

x
5
y



2
2

Anytime we solve a system of
equations we must check our
solution.
We will do this by substituting
the solution back into each
equation for x and y.
x – y = –1
x + 2y = 5
(1) – (2) = –1

(1) + 2(2) =
1+4=5

(1 , 2)
x
Graphing to Solve a Linear System
y
Solve the following system by
graphing:
3x + 6y = 15
–2x + 3y = –3
Using the slope intercept form
of these equations, we can
graph them carefully on graph
paper.
5
1
y = - 2 x+
y = 23 x - 1
(3 , 1)
2
Lastly, we need to verify our solution is
correct, by substituting (3 , 1).
3(3)+ 6 (1) = 15
- 2(3)+ 3(1) = - 3
Label the
solution!
x
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1. Put each equation into y=mx+b (solve for y)
2. Graph each equation on graph paper.
Precision is important, use a ruler!!
3. Determine the point of intersection,
estimate if necessary.
4. Check your solution in both equations!
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Solve the following system of equations by
graphing.
 x y 2

x  2 y  2
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Solve the following system of equations by
graphing.
 2x  y  4

3x  2 y  16
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pg 120 (# 1-9 odd, 25-35 odd, 44)
Four Days
There are two methods of solving a system of
equations algebraically:
◦ Elimination
◦ Substitution
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To solve a system of equations by substitution…
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1. Solve one equation for one of the variables.
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2. Substitute the value of the variable into the other equation.
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3. Simplify and solve the equation for the remaining variable.
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4. Substitute back into either equation to find the value of the
other variable.
● Solve the system: x - 2y = -5
y=x+2
Notice: One equation is already solved for one variable.
Substitute (x + 2) for y in the first equation.
x - 2y = -5
x - 2(x + 2) = -5
● We now have one equation with one variable. Simplify and solve.
x - 2x – 4 = -5
-x - 4 = -5
-x = -1
x=1
● Substitute 1 for x in either equation to find y.
y=x+2
y = 1 + 2 so y = 3
● The solution is (1, 3)
● Let’s check the solution. The answer (1, 3) must check
in both equations.
x - 2y = -5
y=x+2
1 - 2(3) = -5
3=1+2
-5 = -5
3=3
Solve the systems by substitution:
1.
x=4
2x - 3y = -19
2.
3x + y = 7
4x + 2y = 16
3.
2x + y = 5
3x – 3y = 3
4.
2x + 2y = 4
x – 2y = 0
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1. Write each equation in standard form Ax+By=C.
2. Determine which variable you want to eliminate.
3. Multiply an entire equation by a value that will
result in the terms you want to eliminate being
additive inverses.
4. Add the equations. The result is one equation
with one variable.
5. Solve the resulting equation.
6. Substitute the solution into one of the original
equations and solve for the remaining variable.
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Solve the system: 3s - 2t = 10
4s + t = 6
We could multiply the second equation by 2 and the
t terms would be inverses. OR
We could multiply the first equation by 4 and the second equation
by -3 to make the s terms inverses.
Let’s multiply the second equation by 2 to eliminate t. (It’s easier.)
3s - 2t = 10
3s – 2t = 10
2(4s + t = 6)
8s + 2t = 12
Add and solve:
11s + 0t = 22
11s = 22
s=2
Insert the value of s to find the value of t
3(2) - 2t = 10
t = -2
The solution is (2, -2).
Solve the system by elimination:
1.
-4x + y = -12
4x + 2y = 6
2.
5x + 2y = 12
-6x -2y = -14
3.
5x + 4y = 12
7x - 6y = 40
4.
5m + 2n = -8
4m +3n = 2
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pg 128 (# 1-7 odd, 19-27 odd, 31-37 odd)
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The sum of two numbers is 70 and their
difference is 24. Find the two numbers.
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Two angles are supplementary. The measure
of one angle is 10 degrees more than three
times the other. Find the measure of each
angle.
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Two groups go on a whitewater rafting trip.
Group 1 rented 6 rafts and 8 kayaks for a
total of $510. Group 2 rented 3 rafts and 11
kayaks for a total of $465. How much did it
cost to rent each raft and each kayak?
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Applications #1
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Applications #2
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Applications #3
Two Days
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Complete the following warm-up while I
check homework:
Graph the following inequalities:
x  3y  6
y  13 x  2
1. We show the solution to a system of linear inequalities by
graphing them and determining the region that satisfies
all of the individual inequalities simultaneously.
a. This process is easier if we put the inequalities into
Slope-Intercept Form, y = mx + b
2. Graph the line using the y-intercept & slope.
a. If the inequality is < or >, make the lines dotted.
b. If the inequality is < or >, make the lines solid.
3. The solution also includes points not on the line, so you
need to shade the region of the graph:
a. above the line for ‘y >’ or ‘y ’.
b. below the line for ‘y <’ or ‘y ≤’.
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Solve and graph the following system of
inequalities.
3x  4 y  4

 x  2y  2
 y   34 x  1

1
y


2 x 1
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a: 3x + 4y > - 4
3
a : y   x  1
4
a: 3x + 4y > - 4
b: x + 2y < 2
3
a : y   x  1
4
1
b : y   x  1
2
a: 3x + 4y > - 4
b: x + 2y < 2
The region that satisfies
both equations is the
area of overlap. This is
the solution to our
system of inequalities.
Any point in this region
satisfies the system.
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Lets solve the following:
 y  x  3
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 x  y 1
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Jane’s band wants to spend no more than
$575 recording their CD. The studio charges
at least $35 per hour to record. Write and
graph a system of inequalities to represent
this situation.
 y  575
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 y  35 x
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The most Dave can spend on hot dogs and
bun for a cookout is $42. A package of 10
hot dogs costs $3.50. A package of 8 buns
costs $2.50. He needs to buy at least 40 hot
dogs and 40 buns.
◦ Write and graph a system of inequalities that
describes this situation.
◦ Give 3 examples of different purchases he can
make and still satisfy the requirements.
 y  1.4 x  12

x  4
y  5
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Graph the following system of linear
inequalities:
 y  3x  4

 y  x  2
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Graph the following system of linear
inequalities:
y  x

x  2
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Graph the following system of linear
inequalities:
2 x  3 y  9

 x  2y  4
 y  23 x  3

1
y


2 x2
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You work two jobs and can work no more
than a total of 25 hours per week. You make
$8/hr at the first job and $10/hr at the
second job. Your boss at the second job can
only give you 10 hours each week. Write and
graph a system of inequalities assuming that
you need to earn at least $150/week.
 y  .8 x  15
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 y   x  25
 y  10
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pg 136 (# 1-17 odd)
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Practice 3-3 WS (# 1-13 odd)
One Day
1. When we have three equations in a
system, we can use the same two
methods to solve them algebraically as
with two equations.
2. Whether you use substitution or
elimination, you should begin by
numbering the equations!
Solving Systems of Three
Equations
Linear Combination Method
1. Choose two of the equations and eliminate
one variable as before.
2. Now choose one of the equations from step 1
and the other equation you didn’t use and
eliminate the same variable.
3. You should now have two equations (one
from step 1 and one from step 2) that you
can solve by elimination.
4. Find the third variable by substituting the
two known values into any equation.
 x  3 y  3z  4

 2 x  3 y  z  15
 4 x  3 y  z  19
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 2x  y  z  4

 x  3 y  z  11
4 x  y  z  14

 3x  y  z  3

x  y  2z  4
x  2 y  z  4
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pg 157 (# 1-9 odd, 10)
Substitution Method
1. Choose one of the three equations and
isolate one of the variables.
2. Substitute the new expression into each
of the other two equations.
3. These two equations now have the
same two variables. Solve this 2 x 2
system as before.
4. Find the third variable by substituting
the two known values into any
equation.