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Factorisation
David Weeks
© Mathsmadeeasy
Permission given to use for non-commercial use
4 + 8 + 12
4x + 8x + 12x
2t + t3
4y2 + 8y3
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factorisation
Let’s factorise this simple sum
4
First find a common factor
+
8
+
12
= 24
2 is a factor which goes into them
but 4 is a bigger factor. Use that!
Rewrite them all with the factor 4
Now add the brackets and move
the factor 4 outside it to the front
4x1 + 4x2 + 4x3
4 (
1
+
2
+
3)
Now put the rest of each
multiplication inside the brackets
That’s it – we have factorised!
Simplify to check
4 + 8 +12 = 4 ( 1 + 2 + 3 )
4 ( 1 + 2 + 3 ) = 4 (6)
= 24
factorisation
Let’s factorise this simple sum
4x
First find a common factor
+ 8x +
12x
= 24x
2x is a factor which goes into them
but 4x is a bigger factor. Use that!
Rewrite them all with the factor 4x
Now add the brackets and move
the factor 4x outside it to the front
4x x 1 + 4x x 2 + 4x x 3
4x (
1
+
2
+
3)
Now put the rest of each
multiplication inside the brackets
That’s it – we have factorised!
Simplify to check
4x + 8x +12x = 4x( 1 + 2 + 3 )
4x( 1 + 2 + 3 ) = 4x (6)
= 24x
factorisation
Let’s factorise this simple sum
2t
+
2xt
+
First find a common factor
Expand the terms
Look for repeating terms
t3
t x t x t
t appears in both terms
so it’s a factor. Use that!
Add the brackets and move
the factor t outside it to the front
Now put the rest of each
multiplication inside the brackets
That’s it – we have factorised!
t ( 2
+
t ( 2 + t2)
2t + t3 = t ( 2 + t2)
t x t )
factorisation
Let’s factorise this simple sum
4y2
First find a common factor
Expand the terms
Look for repeating terms
8y3
+
4xyxyx1 + 4x2xyxyxy
4 x y x y = 4y2 appears in both
terms so it’s a factor. Use that!
Add the brackets and move
the factor 4y2 outside it to the front
Now put the rest of each
multiplication inside the brackets
That’s it – we have factorised!
4y2 (
1
+
2
x
4y2 ( 1 + 2y)
4y2 + 8y3 = 4y2 ( 1 + 2y)
y )