Transcript Apportionment Methods

Jefferson’s Method
 There are 2 steps to Jefferson’s Method:
1) Find a modified divisor, d, (smaller than the
standard divisor) such that each group’s modified
quota (group’s population divided by d) is rounded
down to the nearest whole number; the sum of the
whole numbers for all the groups is the number of
items to be apportioned. The modified quotients that
are rounded down are called modified lower quotas.
2) Apportion to each group its modified lower quota.
For Example…
 CHS = 1440 students
 30 seats to be apportioned
 Seniors = 328, Juniors = 346, Sophomores = 351,
Freshmen = 415
 Modified Divisor = 46 (less than the S.D. of 48)
 Modified Quotas:
 Seniors = 328/46 = 7.13, Juniors = 346/46 = 7.51
 Soph = 351/46 = 7.63, Fresh = 415/46 = 9.02
Final Answer (Jefferson)
 After rounding down each of the quotas, the
modified lower quotas are:
 Sen (7.13) = 7
 Jun (7.51) = 7
 Soph (7.63) = 7
 Fresh (9.02) = 9
Adams’ Method
 There are 2 steps to Adams’ Method:
1) Find a modified divisor, d, (larger than the
standard divisor) such that when each group’s
modified quota (group’s population divided by d)
is rounded up to the nearest whole number; the sum
of the whole numbers for all the groups is the
number of items to be apportioned. The modified
quotients that are rounded up are called modified
upper quotas.
2) Apportion to each group its modified upper quota.
For Example…
 CHS = 1440 students
 Seniors = 328, Juniors = 346, Sophomores = 351,
Freshmen = 415
 Modified Divisor = 51 (more than the S.D. of 48)
 Modified Quotas:
 Seniors = 328/51 = 6.43, Juniors = 346/51 = 6.78
 Soph = 351/51 = 6.88, Fresh = 415/51 = 8.14
Final Answer (Adams)
 After rounding up each of the quotas, the modified
upper quotas are:
 Sen (6.43) = 7
 Jun (6.78) = 7,
 Soph (6.88) = 7,
 Fresh (8.14) = 9
Homework… something to keep you out
of trouble over the weekend!
 P. 761; #7-13 odd, 14