Lecture Notes: Chapter 5 part 1

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Transcript Lecture Notes: Chapter 5 part 1

DMT 121 – ELECTRONIC
DEVICES
CHAPTER 5:
FIELD-EFFECT
TRANSISTOR (FET)
1
TYPES OF FET
1.


2.


Junction Field-Effect Transistor (JFET)
N-channel
P-channel
Metal Oxide Semiconductor FieldEffect Transistor (MOSFET)
Enhancement-MOSFET
Depletion-MOSFET
2
FET vs BJT
FET
Unipolar device – operate
use only one type of
charge carrier
Voltage-controlled device
– voltage between gate &
source control the current
through device.
High input resistance
BJT
Bipolar device – operate
use both electron & hole
Slower in switching (turnon & off)
Faster in switching (turnon & off)
Current-controlled device –
base current control the
amount of collector
current.
High input impedance
3
THE JFET


BJT – current
controlled, IC is direct
function of IB
FET – voltage
controlled, ID is a direct
function of the voltage
VGS applied to the input
circuit.
FIGURE: (a) Current-controlled and (b)
voltage-controlled amplifiers.
4
JFET




3 terminal:
Drain – upper end
Source – lower end
Gate – 2 p/n-type
regions are diffuse in
the n/p-type material to
form a channel.
FIGURE: A representation of the
basic structure of the two types of
JFET.
5
JFET Structures & Symbols
JFET Structures
JFET Symbols
6
Basic Operation of JFET




VDD provides a drain-to-source voltage and supplies current from drain
to source.
VGG sets the reverse-bias voltage between gate and source.
JFET is always operated with the gate-source pn junction reversebiased.
Reverse-biased of gate-source junction with negative gate voltage
produce a depletion region along pn junction – increase resistance by
restricting the channel width
7
Basic Operation of JFET
Figure: Greater VGG narrows
Figure: Less VGG widens the
the channel (between the
channel (between the white
white areas) which increases
areas) which decreases the
the resistance of the channel
resistance of the channel
and decreases ID.
and increases ID.
8
Basic Operation of JFET



The channel width and the channel resistance can
be controlled by varying the gate voltage –
controlling the amount of drain current, ID.
The depletion region (white area) created by reverse
bias.
Wider toward the drain-end of the channel – reversebias voltage between gate and drain is greater than
voltage between gate and source.
9
JFET Analogy
JFET operation can be compared to a
water spigot.
 The source of water pressure is the
accumulation of electrons at the
negative pole of the drain-source
voltage.

The drain of water is the electron
deficiency (or holes) at the positive
pole of the applied voltage.

The control of flow of water is the
gate voltage that controls the width
of the n-channel and, therefore, the
flow of charges from source to drain.
10
JFET Characteristic
Figure: JFET with VGS=0 V and
variable VDS (VDD)
Figure: Drain Characteristic
11
JFET Characteristics and
Parameters, VGS = 0




VGS = 0 V by shorting the gate to
source (both grounded).
ID increases proportionally with
increases of VDD (VDS increases as
VDD is increased). This is called the
ohmic region (point A to B).
In this area (ohmic region) the
channel resistance is essentially
constant because of the depletion
region is not large enough to have
sufficient effect  VDS and ID are
related by Ohm’s law
In JFET, IG = 0  an important
characteristic for JFET
12
JFET Characteristics and
Parameters, VGS = 0





At point B, the curve levels off and
enter the active region where ID
constant.
Value of VDS at which ID becomes
constant is pinch-off voltage, VP.
As VDD increase from point B to point
C, the reverse-bias voltage from gate
to drain (VGD) produces a depletion
region large enough to offset the
increase in VDS, thus keeping ID
relatively constant.
VDS increase above VP, produce
almost constant ID called IDSS.
IDSS (drain to source current with
gate shorted) is max drain current at
VGS = 0V
13
JFET Characteristics and
Parameters, VGS = 0
• Breakdown occurs at point C
when ID begins to increase
very rapidly with any further
increase in VDS.
• It can result irreversible
damage to the device
• So JFETs are always
operated below breakdown
and within the constantcurrent area (between points
B and C on the graph)
14
VGS controls ID
15
VGS controls ID




As VGS is set to increasingly more negative by
adjusting VGG. A family of drain characteristic curves
is produced.
Notice that ID decrease as the magnitude of VGS is
increased to larger negative value narrowing of
channel.
For each increase in VGS, the JFET reaches pinchoff (constant current begins) at values of VDS less
than VP.
The amount of drain current is controlled by VGS.
16
Cutoff Voltage




Value of VGS that makes ID
≈ 0A is the cutoff voltage,
VGS(off).
JFET must operated
between VGS=0V and
VGS(off).
In n-channel JFET: VGS
has large –ve value, ID is
reduce to zero.
Cutoff effect due to
widening of depletion
region.
17
VGS controls ID
18
Pinch-Off & Cutoff Voltage




Pinch-off voltage, VP = value of VDS at
which drain current becomes constant
and equal to IDSS at VGS = 0V
Pinch-off occurs for VDS value less than
VP when VGS is nonzero.
VGS(off) & VP are equal in magnitude but
opposite sign
VGS(off) = -VP
19
P-channel JFET operation

Same as n-channel
JFET except required
negative VDD and
positive VGS.
20
EXAMPLE
VGS(off)= -4V and IDSS=
12mA. Determine the
minimum value of VDD
required to put the
device in constantcurrent region of
operation when VGS=
0V.
21
JFET Transfer Characteristic
22
JFET Transfer Characteristic





The transfer characteristic of input-to-output is not as
straightforward in a JFET as it is in a BJT.
In a BJT,  indicates the relationship between IB
(input) and IC (output).
Control Variable
IC = IB
constant
In a JFET, the relationship of VGS (input) and ID
(output) is a little more complicated:
ID 
 V 
I DSS  1  GS 

V P 

Constant
2
Control Variable
23
JFET Transfer Curve
This graph shows the value of ID for a given value of VGS.
When VGS = 0; ID = IDSS
When VGS = VGS (off) = VP; ID = 0 mA
24
Plotting JFET Transfer Curve
Step 1
Solving for VGS = 0V

V
I D  I DSS  1  GS
VP

ID = IDSS
Step 2



2

V
I D  I DSS  1  GS
VP

Solving for VGS = Vp (VGS(off)) ID = 0A



2
Step 3
Solving for VGS = 0V to Vp

V
I D  I DSS  1  GS
VP

25



2
EXAMPLE
JFET with IDSS = 9 mA and VGS(off) = -8V
(max). Determine ID for VGS = 0V, -1V
and -4V.
ANSWER:
VGS = 0V, ID = 9mA
VGS = -1V, ID = 6.89mA
VGS = -4V, ID = 2.25mA
26
JFET Biasing
Just as we learned that the bipolar junction transistor
must be biased for proper operation, the JFET too must
be biased for operation. Let’s look at some of the
methods for biasing JFETs. In most cases the ideal Qpoint will be the middle of the transfer characteristic
curve which is about half of the IDSS.
JFET
ID  IDSS (1 
I D = IS
IG  0 A
VGS 2
)
VP
BJT
IC = IB
IC  IE
VBE  0.7 V
27
JFET Biasing


JFET must be operated that gate-source junction is
always reverse-biased.
VG=0V
28
Self-Bias






Since VG = 0V, IG = 0A
IS = ID
VS = IDRS
VGS = VG – VS = 0 – IDRS = -IDRS
VD = VDD – IDRD
VDS = VD – VS = VDD – ID(RD + RS)
29
JFET Biasing, Fixed- Bias
Configuration
IG = 0 so VRG = IGRG = (0 A)RG = 0 then RG can be removed from the
circuit.
RG only need in ac analysis through the input Vi
- VGG – VGS = 0
VGS = - VGG
30
JFET Biasing, Fixed- Bias
Configuration
Drain-to-source voltage can be determined by
applying Kirchoff’s voltage law
VDS + IDRD –VDD = 0
VDS = VDD – IDRD
Source voltage to ground; VS = 0
Drain-to-source voltage can also be
determined through;
VDS = VD – VS but VS = 0 then
VDS = VD
Fig. 7.5 Measuring the quiescent
values of ID and VGS.
Gate-to-source voltage
VGS = VG – VS ; since VS = 0
VGS = VG
Since the configuration requires two dc supply, its use is limited and
not included in the list of common FET configurations.
31
JFET Biasing, Self- Bias
Configuration
Most common type of JFET bias. Eliminates the need for two dc supplies.
The controlling gate-to-source is determined by the voltage across a resistor
RS.
For analysis, resistor RG replaced by a short circuit equivalent since IG = 0 A.
32
JFET Biasing, Self- Bias
Configuration
Voltage drop across source resistor, RS
VRS = ISRS; since IS = ID then
VRS = IDRS
For indicated closed loop in the Figure 7.9
-VGS – VRS = 0
VGS = - VRS
VGS = -IDRS
Drain current, ID:
Fig. 7.9 DC analysis of
the self-bias configuration.
I D  I DSS (1 
VGS 2
)
VP
I D  I DSS (1 
 I D RS 2
)
VP
I D  I DSS (1 
I D RS 2
)
VP
33
JFET Biasing, Self- Bias
Configuration
Voltage between drain-to-source, VDS
VDD – IDRD – VDS – ISRS = 0
Since IS = ID
VDD – IDRD – VDS – IDRS = 0
VDS = VDD – ID(RD + RS)
OR
VDS = VD – VS
VS = ISRS and VD = VDD – IDRD
Fig. 7.9 DC analysis of
the self-bias configuration.
Voltage between gate-to-source, VGS
VGS = VG – VS;
Since VG = 0
VGS = -VS and VS = ISRS
Then VGS = - ISRS
34
JFET Biasing, Self- Bias
Configuration
The value of RS needed to
establish the computed VGS
can be determined by the
previously discussed
relationship below.
RS = | VGS/ID |
The value of RD needed can be
determined by taking half of
VDD and dividing it by ID.
RD = (VDD/2)/ID
35
JFET Biasing, Self- Bias
Configuration
Remember the purpose of biasing
is to set a point of operation (Qpoint). In a self-biasing type JFET
circuit the Q-point is determined
by the given parameters of the
JFET itself and values of RS and
RD. Setting it at midpoint on the
drain curve is most common.
One thing not mentioned in the
discussion was RG. It’s value is
arbitrary but it should be large
enough to keep the input
resistance high.
36
JFET Biasing, Voltage-Divider
Configuration
The basic construction exactly the
same with BJT, but the dc analysis
quite different with IG = 0 for FET
The voltage at source, VS must be
more positive than the voltage at
the gate, VG in order to keep gatesource junction reverse-biased.
37
JFET Biasing, Voltage-Divider
Configuration
Gate-to-source analysis
VG  (
R2
)VDD
R1  R2
VS = IDRS
Gate-to-source voltage; VGS = VG – VS
And source voltage is VS = VG – VGS
The drain current can be expressed as
ID 
VS VG  VGS

RS
RS
38
JFET Biasing, Voltage-Divider
Configuration
Drain-to-source analysis
VDS = VDD – ID(RD + RS)
VD = VDD – IDRD
VS = IDRS
I R1  I R 2
VDD

R1  R2
39