Transcript +95%

Economics of the Firm
Some Introductory Material
Introducing homo economicus….also known as
“Economic Man”
Economic man is a RATIONAL being
Every decision we make involves both incremental benefits and
costs…if we are acting rationally, we will undertake any action where
the benefits outweigh the costs.
Example:
Suppose that you have
been wandering in the
desert for 5 days when
you come across a
lemonade stand. How
much would you pay for a
glass of lemonade?
Suppose that you have been wandering in the desert for 5 days when you
come across a lemonade stand. How much would you pay for a glass of
lemonade?
“Utility” is a function of lemonade (among other things)
U L,  
A glass of lemonade will raise
your utility…
MU L
A glass of lemonade isn’t
free..it has a price
PL
You will buy a glass of lemonade as long as
the benefits are greater than the costs
We can complicate the example by adding
an alternative choice…a hot dog stand
“Utility” is a function of lemonade and hot dogs (among
other things)
U L, H ,  
A glass of lemonade will raise
your utility…
MU L
PL
Every dollar spent on lemonade is a
dollar that won’t be spent on hot
dogs
MU H
PH
You will buy a glass of lemonade as long as
the benefits are greater than the costs
In either case, we can say that, given a
representation of individual tastes, price
should have a negative relationship with
quantity purchased
“Utility” is a function of lemonade and hot dogs (among
other things)
U L, H ,  
Rational Behavior
(-) (+)
QD  DPL , PH 
Purchases of lemonade are negatively related to the
price of lemonade and positively related to the price of
hot dogs
We can easily add another variable to our demand
story…most of us are constrained by our disposable
income.
Expenditures
on Lemonade
Expenditures
on Hot Dogs
Available
Income
PL L  PH H  I
(Constraint)
U L, H ,  
(Preferences)
+
Rational Behavior
(-) (+) (+)
QD  DPL , PH , I 
Purchases of lemonade are negatively related to the price of lemonade and
positively related to income and the price of hot dogs
We have a similar situation on the supply side…with one complication.
Stockholders/Bondholders
provide capital for the firm
Stockholders/Bondholders
receive payments from the
firm
Managers
provide
effort to the
firm
Managers receive
compensation from
the firm
Stockholders own the company,
but managers make the
decisions…how do we align their
incentives?
If we assume that the institutional details have been worked
out, then the job of the decision maker is to maximize firm value
Profits one
year in the
future
Profits two
years in the
future
3
1
2
FV   0 


 ...
2
3
1  r 1  r  1  r 
Current Profits
Risk adjusted
rate of return
While it is not necessary, it is sufficient to say that maximizing
each year’s profits will maximize firm value
Variable costs are
influenced by
sales decisions
  PLQ  VC  FC
Price times
quantity equals
current revenues
Fixed costs
(overhead) is not
affected by the
level of sales and,
hence, has no
impact on sales
decisions
As with the average consumer, a firm’s decisions are made at the margin!!!
For each sale that is made, it must be profitable at the margin.
For now, lets assume that the firm has no control over the price
it charges
  PLQ  VC  FC
How does an additional
sale affect revenues?
PL
How does an additional
sale affect costs?
MC
A sale will be made as long as it has a bigger
impact on revenues than costs.
As with the average consumer, a firm’s decisions are made at the margin!!!
In either case, we can say that, given a representation of a firm’s cost
structure, price should have a positive relationship with sales (higher price
raises profit margin) while anything that influences costs at the margin
should have a negative relationship with sales
Costs are a function of wages, material prices, etc.
  PLQ  VC  FC
Rational Behavior
(+) (-)
QS  S PL , MC 
Sales of lemonade are positively related to the price of
lemonade and negatively related to marginal costs
A Demand Function represents the rational decisions made by
a representative consumer(s)
“Is a function of”
Quantity
Purchased
QD  DPL , I 
Market
Price (-)
For example, suppose that at a market
price of $2.50, an individual with an
annual income of $50,000 chooses to
buy 5 glasses of lemonade per week.
Income (+)
5  D$2.50,$50,000
A Demand Curve is simply a graphical representation of a
demand function
For example, suppose that at a market
price of $2.50, an individual with an
annual income of $50,000 chooses to
buy 5 glasses of lemonade per week.
Price
DI  $50,000
$2.50
Quantity
5
5  D$2.50,$50,000
A Demand Curve is simply a graphical representation of a
demand function
Suppose that an increase in the market
price from $2.50 to $2.75 causes this
individual to reduce his/her lemonade
purchases to 4 glasses per week
Price
$2.75
$2.50
DI  $50,000
Quantity
4
5
4  D$2.75,$50,000
Demand curves slope downwards – this reflects the negative relationship between price
and quantity. Elasticity of Demand measures this effect quantitatively
%Q  20
D 

 2
% P
10
Price
 2.75  2.50 

 *100  10%
2.50 

$2.75
$2.50
DI  $50,000
Quantity
4
5
 45

 *100  20%
5


A Supply Function represents the rational decisions made by a
representative firm(s)
“Is a function of”
QS  S PL , MC 
Quantity
Supplied
Market
Price (+)
For example, suppose that at a
market price of $2.00, a firm facing a
wage rate of $6/hr will supply 200
glasses per week.
Marginal Costs (-)
200  S $2.00,$6
A Supply Curve is simply a graphical representation of a supply
function
For example, suppose that at a
market price of $3.00, a firm facing a
wage rate of $6/hr will supply 200
glasses of lemonade per week.
Price
S C  $6
$2.00
Quantity
200
200  S $3.00,$6
A Supply Curve is simply a graphical representation of a supply
function
Suppose that an increase in the market
price from $3.00 to $3.90 causes this
firm to increase it’s lemonade sales to
250 cups per week
S C  $6
Price
$3.00
$2.00
Quantity
200
250
250  S $3.50,$6
Supply curves slope upwards – this reflects the positive relationship between price and
quantity. Elasticity of Supply measures this effect quantitatively
S C  $6
Price
 3.00  2.00 

 *100  50%
2
.
00


$3.00
$2.00
Quantity
200
%QS 25
s 

 .5
%P 50
250
 250  200 

 *100  25%
200


Suppose that the overall market consists of
5,000 identical lemonade drinkers and 100
lemonade suppliers
Price
$2.75
At a price of $2.50, each
of the 5,000 lemonade
drinkers buys 5 glasses per
week.
$2.50
DI  $50,000
Quantity
20,000 25,000
S C  $6
Price
At a price of $3.00, each
of the 100 lemonade
suppliers is willing to sell
250 glasses per week.
$3.00
$2.00
Quantity
20,000
25,000
Given the behavior of suppliers and
consumers, the market price would need
to settle in between $2.50 and $2.75
S C  $6
Price
$2.00
DI  $50,000
At a price of $2.00, total
supply is 20,000, but
demand is at least 25,000
Quantity
20,000
Q>25,000
Given the behavior of suppliers and
consumers, the market price would need
to settle in between $2.50 and $2.75
S C  $6
Price
$3.00
At a price of $3.00, total
supply is 25,000, but
demand is less than 20,000
DI  $50,000
Quantity
Q<20,000
25,000
Given the behavior of suppliers and
consumers, the market price would need
to settle in between $2.50 and $2.75
S C  $6
Price
22,500  S $2.60, C  $6  D$2.60, I  $50,000
$2.60
DI  $50,000
Quantity
22,500
We would call the $2.60 price the
equilibrium price
Suppose that average income in the area
rose to $75,000. Higher income levels
should raise demand at any market price
S C  $6
Price
At the current $2.60 market price,
supply is still 22,500, but with a
higher level of income, demand has
risen to 28,000
$2.60
DI  $75,000
DI  $50,000
Quantity
22,500
28,000
At the new income level of $75,000, $2.60 can no longer be
the equilibrium price
Suppose that average income in the area
rose to $75,000. Higher income levels
should raise demand at any market price
S C  $6
Price
25,000  S $3.00, C  $6  D$3.00, I  $75,000
$3.00
$2.60
DI  $75,000
DI  $50,000
Quantity
22,500 25,000
The increase in income causes a rise in sales and a rise in
market price
Suppose that lemonade store wages rose
to $10/hr. Higher wages should lower
supply at any market price
S C  $6
Price
At the current $2.60 market price,
supply has fallen to 18,000, but
demand is still at 22,500
$2.60
DI  $50,000
Quantity
18,000
22,500
At the wage level of $10, $2.60 can no longer be the
equilibrium price
Suppose that lemonade store wages rose
to $10/hr. Higher wages should lower
supply at any market price
S C  $6
Price
20,000  S $2.75, C  $10  D$2.75, I  $50,000
$2.75
$2.60
DI  $50,000
Quantity
20,000 22,500
Higher wages cause a rise in market price and a drop in sales
Supply, Demand, and equilibrium prices/sales
PL L  PH H  I
(Constraint)
U L, H ,  
(Preferences)
+
Rational Behavior
  PQ  VC  FC
Rational Behavior
(+) (-)
QS  S P, MC 
(-) (+)
QD  DPL , I 
With the additional assumption that prices adjust and that markets clear (equilibrium), we
have the following…
(+) (-)
Q  QI , MC 
P  PI , MC 
(+) (+)
Sales are related to average income and marginal costs
Prices are related to average income and marginal costs
If we truly believe in competitive markets, we can sleep well at nigh knowing several
things…goods are being produced by the most efficient producers (i.e. those with the
lowest costs) and given to individuals with the highest values.
Somebody who bought a glass of
lemonade paid $2.60 when they
actually valued it at much higher. We
call this consumer surplus
Price
S
P*  $2.60
Somebody who sold this glass of
lemonade collected $2.60 when the
marginal production cost was much
lower. We call this producer surplus
(a.k.a Profit)
D
Q*  22,500
Q  17,750
Quantity
We also can rest assured that we are producing exactly the right goods and services
Price
S
P*  $2.60
Price
S
P*  $2.60
D'
D'
Q*  22,500
Lemonade
D
D
Quantity
Q*  22,500
Quantity
Hot Dogs
If consumer preferences suddenly shifted away from lemonade and towards hot
dogs, the lemonade market would shrink (as the price of lemonade falls) while the
hot dog market expands (and the price rises)
Can we use our market model
to explain differences in
salaries?
Kobe Bryant:
Salary = $23,000,000,000
High School Teacher:
Salary = $50,000
Price
S
Price
S
$50K
$23M
D
D
Quantity
$15K
3,000,000
Quantity
1
Microsoft’s new Xbox 360 gaming console was released in North America on November
22 at a retail price of $299.99. Available supply sold out almost immediately as
Christmas shoppers stood in line for this year’s hot item. (Microsoft has increased its
sales target from 3M units to 6M units).
What’s odd about this??
Why didn’t Microsoft raise their price?
S
Price
???
$299.99
D
Quantity
3M
Clearly, $299.99 is not an
equilibrium price !
When do our rationality assumptions begin to break down?
Situations involving interactions among small groups of people:
Example: How to split $20.
Situations involving the immediate present vs. the future:
Example: Instant gratification and the time value of money
Situations involving uncertainty
Example: The Monty Hall Problem
And now for something
completely different….
What are the odds that a fair coin flip results in a head?
What are the odds that the toss of a fair die results in a 5?
What are the odds that tomorrow’s temperature is 95 degrees?
The answer to all these questions come from a probability distribution
Probability
1/2
Head
Tail
Probability
1/6
1
2
3
4
5
6
A probability
distribution is a
collection of
probabilities
describing the odds of
any particular event
The distribution for temperature in south bend is a bit more complicated because there
are so many possible outcomes, but the concept is the same
Probability
Standard Deviation
Temperature
Mean
We generally assume a Normal Distribution which can be characterized by a
mean (average) and standard deviation (measure of dispersion)
Without some math, we can’t find the probability of a specific outcome, but we
can easily divide up the distribution
Probability
Temperature
Mean-2SD
2.5%
Mean -1SD
13.5%
Mean
34%
Mean+1SD
34%
Mean+2SD
13.5%
2.5%
Annual Temperature in South Bend has a mean of 59 degrees and a standard deviation
of 18 degrees.
Probability
95 degrees is 2 standard deviations
to the right – there is a 2.5% chance
the temperature is 95 or greater
(97.5% chance it is cooler than 95)
Temperature
23
41
Can’t we do a little better than this?
59
77
95
Conditional distributions give us probabilities conditional on some observable information – the
temperature in South Bend conditional on the month of July has a mean of 84 with a standard
deviation of 7.
Probability
95 degrees falls a little more than
one standard deviation away (there
approximately a 16% chance that
the temperature is 95 or greater)
Temperature
70
77
84
91 95
Conditioning on month gives us a more accurate forecast!
98
We know that there should be a “true” probability distribution that
governs the outcome of a coin toss (assuming a fair coin)
PrHeads  PrTails   .5
Suppose that we were to flip a coin over and over again and after
each flip, we calculate the percentage of heads & tails
# of Heads
Total Flips
(Sample Statistic)
.5
(True Probability)
That is, if we collect “enough” data, we can eventually learn the truth!
We can follow the same process for the temperature in South Bend
Temperature ~

N , 2

We could find this distribution by collecting temperature data for south bend
Sample Mean
(Average)
Sample
Variance
1N
x    xi  
 N  i 1
N
1


2
s 2     xi  x    2
 N  i 1
Note: Standard Deviation is the square root of the variance.
Conditional Distributions
Obviously, the temperature in
South Bend is different in the
winter and the summer. That is,
temperature has a conditional
distribution
Temp (Summer) ~
Temp (Winter) ~

N  s,

N  W ,  W2
Regression is based on the estimation of conditional distributions


2
s
Some useful properties of probability distributions

x  N μ,σ 2
y  kx
Probability distributions
are scalable


y  N k,k 2σ 2

=
3X
Mean = 1
Mean = 3
Variance = 4
Variance = 36 (3*3*4)
Std. Dev. = 2
Std. Dev. = 6
 
y  N  ,σ 
x  y  N    ,σ
x  N μ x ,σ x2
Probability distributions
are additive
y
2
y
x
y
2
x
 σ y2  2 cov xy
=
+
Mean = 1
Mean = 2
Mean = 3
Variance = 1
Variance = 9
Variance = 14 (1 + 9 + 2*2)
Std. Dev. = 1
Std. Dev. = 3
Std. Dev. = 3.7
COV = 2

Suppose we know that the value of a car is determined by its age
Value = $20,000 - $1,000 (Age)
Car Age
Value
Mean = 8
Mean = $ 12,000
Variance = 4
Variance = 4,000,000
Std. Dev. = 2
Std. Dev. = $ 2,000
We could also use this to forecast:
Value = $20,000 - $1,000 (Age)
How much should a six
year old car be worth?
Value = $20,000 - $1,000 (6) = $14,000
Note: There is NO uncertainty in this
prediction.
Searching for the truth….
You believe that there is a relationship between age and value,
but you don’t know what it is….
1. Collect data on values and age
2. Estimate the relationship
between them
Note that while the true distribution of age is N(8,4), our
collected sample will not be N(8,4). This sampling error will
create errors in our estimates!!
18000.00
16000.00
Slope = b
14000.00
12000.00
10000.00
a
8000.00
6000.00
4000.00
2000.00
0.00
0
2
4
6
Value = a + b * (Age) + error
8
10
12
14

error  N 0,σ 2
We want to choose ‘a’ and ‘b’ to minimize the error!

Regression Results
Variable
Intercept
Age
Coefficients
Standard Error
t Stat
12,354
653
18.9
- 854
80
-10.60
We have our estimate of “the truth”
Value = $12,354 - $854 * (Age) + error
Intercept (a)
Age (b)
Mean = $12,354
Mean = -$854
Std. Dev. = $653
Std. Dev. = $80
T-Stats bigger
than 2 in
absolute value
are considered
statistically
significant!
Regression Statistics
R Squared
0.36
Standard Error
2250
Percentage of value
variance explained by
age
Error Term
Mean = 0
Std, Dev = $2,250
We can now forecast the value of a 6 year old car
6
Salary = $12,354 - $854 * (Age) + error
Mean = $12,354
Mean = $854
Mean = $0
Std. Dev. = $653
Std. Dev. = $ 80
Std. Dev. = $2,250
StdDev  Var a   X 2Var b   2 XCova, b   Var error 
Cova, b   XVarb
 
(Recall, Shoe size has a mean of 6)
StdDev  6532  6 2 80 2  26880 2  2250 2  $2,259
Value  12,354  854 * 6  $7,230
StdDev  653
2
 6 80
2
2
2
2



 2 6 8 80  2250
 $2,259
Value
+95%
Forecast Interval
-95%
Age  6
x 8
Age
Note that your forecast error will always be smallest at the sample mean! Also, your forecast
gets worse at an increasing rate as you depart from the mean
What are the odds that Pat Buchanan received 3,407 votes from Palm
Beach County in 2000?
The Strategy: Estimate a
conditional distribution for Pat
Buchanan’s votes using every
county EXCEPT Palm Beach
Using Palm Beach data,
forecast Pat Buchanan’s
vote total for Palm
Beach
The Data: Demographic Data By County
County
Black
(%)
Age 65
(%)
Hispanic
(%)
College
(%)
Income
(000s)
Buchanan Total
Votes
Votes
Alachua
21.8
9.4
4.7
34.6
26.5
262
84,966
Baker
16.8
7.7
1.5
5.7
27.6
73
8,128
LN P   a1  a2 B  a2 A65  a3 H  a4C  a5 I  
Buchanan Votes
Total Votes
Error term
*100
Parameters to be estimated
Side note: Why logs?
Option #1: Linear
P  3 .5B
A 10% increase in the
black percentage (say,
from 30% to 40%)
increases Pat
Buchanan’s vote
percentage by 5%
(Say, from 1% to 6%)
P = Buchanan’s Vote Percentage
B = Percentage Black
Option #2: Semi –Log
Linear
LN P  3 .5B
A 10% increase in the
black percentage (say,
from 30% to 40%)
increases Pat
Buchanan’s vote
percentage by 5%
(Say, from 1% to
1(1.05) = 1.05%)
Option #3: Log
Linear
LN P  3 .5LN B
A 10% increase in the
black percentage (say,
from 30% 30(1.10) =
33% increases Pat
Buchanan’s vote
percentage by 5%
(Say, from 1(1.05) =
1.05%)
The Results:
Variable
Coefficient
Standard Error
t - statistic
Intercept
2.146
.396
5.48
Black (%)
-.0132
.0057
-2.88
Age 65 (%)
-.0415
.0057
-5.93
Hispanic (%)
-.0349
.0050
-6.08
College (%)
-.0193
.0068
-1.99
.00113
-4.58
Income (000s) -.0658
LN P   2.146  .0132B   .0415 A65   .0349H   .0193C   .0658I 
Now, we can make a forecast!
County
Black
(%)
Age 65
(%)
Hispanic
(%)
College
(%)
Income
(000s)
Buchanan Total
Votes
Votes
Palm Beach
21.8
23.6
9.8
22.1
33.5
3,407
431,621
LN P   2.146  .0132B   .0415 A65   .0349H   .0193C   .0658I 
LN P  2.004
P  e 2.004  .134%
.00134431,621  578
This would be our prediction for Pat
Buchanan’s vote total!
LN P  2.004
We know that the log of Buchanan’s vote percentage is
distributed normally with a mean of -2.004 and with a
standard deviation of .2556
Probability
LN(%Votes)
-2.004 – 2*(.2556)
= -2.5152
-2.004 + 2*(.2556)
= -1.4928
There is a 95% chance that the log of Buchanan’s vote
percentage lies in this range
P  e 2.004  .134%
Next, lets convert the Logs to vote percentages
Probability
% of Votes
e
2.5152
 .08%
e
1.4928
 .22%
There is a 95% chance that Buchanan’s vote percentage lies in
this range
.00134431,621  578
Finally, we can convert to actual votes
Probability
.0008431,621  348
Votes
.0022431,621  970
There is a 95% chance that Buchanan’s total vote lies in this
range