PPT - Electrical and Computer Engineering

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Transcript PPT - Electrical and Computer Engineering

EE4271
VLSI Design
Dr. Shiyan Hu
Office: EERC 731
The Wires
Adapted and modified from Digital Integrated Circuits: A Design Perspective
by Jan M. Rabaey, Anantha Chandrakasan, and Borivoje Nikolic.
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1
Modern Interconnect
receivers
transmitters
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Modern Interconnect - II
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Interconnect Delay Dominates
Delay (psec)
300
250
Interconnect delay
200
150
100
Transistor/Gate delay
50
0
0.8
0.5
0.35 0.25
Technology generation (m)
Source: Gordon Moore, Chairman Emeritus, Intel Corp.
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Wire Model
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Capacitor
A
capacitor is a device that can store an
electric charge by applying a voltage
 The capacitance is measured by the
ratio of the charge stored to the applied
voltage
 Capacitance is measured in Farads
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3D Parasitic Capacitance

Given a set of conductors, compute the
capacitance between all pairs of conductors.
-
+
+
+
-
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1V
+
+
-
- -
C=Q/V
-
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Simplified Model
Area capacitance
(Parallel plate): area
overlap between
adjacent layers/substrate
 Fringing/coupling
capacitance:

 between side-walls on the
same layer
 between side-wall and
adjacent layers/substrate
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m3
m2
m2
m2
m1
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The Parallel Plate Model (Area Capacitance)
c
 di
t di
Current flow
WL
L
Electrical-field lines
W
H
tdi
Dielectric
Substrate
Capacitance is proportional to the overlap between the
conductors and inversely proportional to their separation
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Wire Capacitance
 More
difficult due to multiple layers,
different dielectric
=8.0
multiple
dielectric
m3
=4.0
m2 =3.9 m2 m2
=4.1
m1
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Simple Estimation Methods - I
C
= Ca*(overlap area)
+Cc*(length of parallel run)
+Cf*(perimeter)
 Coefficients Ca, Cc and Cf are given by
the fab
 Cadence Dracula
 Fast but inaccurate
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Simple Estimation Methods - II
 Consider
interaction between layer i
and layers i+1, i+2, i–1 and i–2
 Cadence Silicon Ensemble
 Accuracy 50%
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Library Based Methods
 Build
a library of tens of thousands of
patterns and compute capacitance for
each pattern
 Partition layout into blocks, and match
with the library
 Accuracy 20%
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Accurate Methods In Industry
 Finite
difference/finite element method
 Most accurate, slowest
 Raphael
 Boundary
element method
 FastCap, Hicap
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Fringing versus Parallel Plate
Fringing/Coupli
ng capacitance
dominates.
(from [Bakoglu89])
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Wire Resistance

Basic formula R=(/h)(l/w)
l
h
w
  : resistivity
 h: thickness, fixed for a given technology and layer
number
 l: conductor length
 w: conductor width
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Sheet Resistance

Simply R=(/h)(l/w)=Rs(l/w)
l
w
 Rs: sheet resistance Ohms/square, where h is the
metal thickness for that metal layer. Given a
technology, h is fixed at each layer.
 l: conductor length
 w: conductor width
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Typical Rs (Ohm/sq)
Min
Typical
Max
M1, M2
0.05
0.07
0.1
M3, M4
0.03
0.04
0.05
Poly
15
20
30
Diffusion 10
25
100
N-well
2000
5000
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1000
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Contact and Via

Contact:
 link metal with diffusion (active)
 Link metal with gate poly

Via:
 Link wire with wire
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Interconnect
Delay
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Analysis of Simple RC Circuit
i(t)
R
R  i (t )  v (t )  vT (t )
vT(t) ±
C
d (Cv(t ))
dv (t )
i (t ) 
C
dt
dt
dv (t )
 RC
 v (t )  vT (t )
dt
state
variable
Input
waveform
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v(t)
Analysis of Simple RC Circuit
Step-input response:
v0
v0u(t)
v0(1-e-t/RC)u(t)
dv(t )
 v(t )  v0u (t )
dt
t
v(t )  Ke RC  v0u(t )
RC
match initial state:
v(0)  0
 K  v0u (t )  0  K  v0  0
output response for step-input:
v(t )  v0 (1  e
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t
RC
)u (t )
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0.69RC

v(t) = v0(1 - e-t/RC) -- waveform
under step input v0u(t)

v(t)=0.5v0  t = 0.69RC
 i.e., delay = 0.69RC
(50% delay)
v(t)=0.1v0  t = 0.1RC
v(t)=0.9v0  t = 2.3RC
 i.e., rise time = 2.2RC (if defined as time from 10% to 90% of Vdd)


For simplicity, industry uses
TD = RC
(= Elmore delay)
We use both RC and 0.69RC in this course. In textbook, it
always uses 0.69RC.
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Elmore Delay
Delay
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1. 50%-50%
point delay
2. Delay=RC
(Precisely,
0.69RC)
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Elmore Delay - III
What is the
delay of a wire?
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Elmore Delay – IV
Assume: Wire modeled by N equal-length segments
For large values of N:
Precisely,
should be
0.69RC/2
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Elmore Delay - V
n2
n1
n1
n2
C/2
R
C/2
R=unit wire resistance*length
C=unit wire capacitance*length
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RC Tree Delay
4
4
2
2
7
7
2
24+4*2=32
1
1
Unit wire cap=1, unit wire res=1
3.5
2*(1+3.5+3.5+2+2)=24
RC Tree Delay=max{32,48.5}=48.5
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3.5
2
24+7*3.5=48.5
Precisely,
0.69*48.5
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More Accurate RLC Delay Model
I=V/R at t=0
is not right
since you
assume that
you can see
R with 0 time
At time t=0, switch is on. This effect is not felt everywhere
instantaneously. Rather, the effect is propagated with a speed
u. Denote by c0 the speed of light, epsilon the permittivity and
mu the permeability of the dielectric of the medium which the
wire is in, L and C the unit wire inductance and capacitance,
respectively. According to Maxwell’s law,
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RLC Delay - II
Voltage and
Current at
time t1 and t2
R0 is the resistance
you can really see at
t1. R cannot be seen
yet.
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RLC Delay - III
 What
is R0?
 The front of the voltage travels from 0 to
l. Suppose that the distance it moves is
dx, the capacitance to be charged is
Cdx. The charge is thus dQ=CdxV.
 Current I=dQ/dt=CVdx/dt=CVu
 where
is called characteristic
impedance.
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RLC Delay - IV
 R0
is a function of the medium
 For Printed Circuit Board (PCB), it is
about 50-75 ohm
 For any x between 0 and l, we always
have Ix=Vx/R0,Il=Vl/R0 when x=l
 Note that there is a resistor R. We
should have Il=Vl/R
 What happens if R!= R0?
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RLC Delay - V






At load, the wave will be reflected back to the source.
The amplitude and polarity of this reflected wave are such
that the total voltage, the sum of incident voltage and
reflected voltage, satisfies Il=Vl/R
If the incident voltage is V, denote by pV the reflected
voltage, where p is called the reflection coefficient.
If incident current is V/R0, then reflected current is –pV/R0
Thus, (V+pV)/(V/R0–pV/R0)=R.
p=(R/R0-1)/(R/R0+1)
 R=R0, p=0, no reflection
 R=infty, p=1, wire is unterminated
 R=0, p=-1, wire is short-circuited

There can be multiple rounds of reflections.
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RLC Delay Example








Consider a wire of length l, R0=100 ohm, R=900 ohm driven by the
source resistance (transistor equivalent resistance) Rs= 14 ohm.
Source voltage is 12V as a step input at time t=0. We want to compute
the waveform at the end of l.
Rs=14
Reflection coefficient
At t=0, V1=12*R0/(R0+Rs)=10V since it cannot see R yet
At t=td=l/u, wave V1 arrives at the end and is reflected as
V2=pRV1=8V. The total voltage at the end is V1+V2 =18V
At time t=2td, wave V2 arrives at the source and reflected as
V3=pSV2=-0.75*8=-6V
At time t=3td, wave V3 arrives at the end and is reflected as
V4=PRV3=-4.8V, so the total voltage at the end is V1+V2+V3+V4=7.2V
Continues this process. Next total voltage at the end is 13.7V.
The total voltage at l will converge to 12*R/(R+Rs)=11.7V
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RLC Delay Example - II
Voltage at the end of l
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When To Use RLC Model
v0
v0u(t)
v0(1-e-t/RC)u(t)
RC Model, V0=12





The voltages at first few td have large magnitudes and are
quite different from RC model. This is because Rs<R0.
When Rs>>R0, V1 is small and is the reflected voltage V2.
The total voltage at the end of the wire will gradually
increase to 11.7V, which is the same as predicted by RC
model.
Thus, RLC model should only be used when Rs is small
(see also Figure 4-21 in the textbook) since RLC model is
expensive to compute.
RLC model can be used when the switching is fast
enough since signal transition time is proportional to Rs.
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Summary

Wire capacitance
 Fringing/coupling capacitance dominates area capacitance


Wire resistance
RC Elmore delay model for wire
 For single wire, 0.69RC/2
 RC tree

RLC model for wire
 Reflection
 When to use
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